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3 years ago

A marathon is 131\5 miles long. If 4 people divide the distance equally, how many miles does each person need to run?

Mathematics

1 answer:

jarptica [38.1K]3 years ago

6 0

Answer:

328.75 miles

Step-by-step explanation:

Step one:

given data

A marathon is 131\5 miles long (note the format of the length of the marathon 1315 miles)

We are required to divide the length of the marathon by 4

=1315/4

=328.75 miles

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Mr. McGloughlin’s horses eat a total of 19 liters 2 deciliters of rolled oats, and drink a total of 46 liters 4 deciliters of wa

Hunter-Best [27]

Answer:

459.2 liters.

Step-by-step explanation:

Let us convert our given amount of rolled oats and water in deciliters.

1 liter = 10 deciliters

19 liters = 19*10 deciliters = 190 deciliters.

$\text{Total amount of rolled oats consumed per day}=(190+2)\text{ deciliters}$

$\text{Total amount of rolled oats consumed per day}=192\text{ deciliters}$

46 liters=46*10=460 deciliters

$\text{Total amount of water consumed per day}=(460+4)\text{ deciliters}$

$\text{Total amount of water consumed per day}=464\text{ deciliters}$

Now let us find weekly consumption of oats and water by multiplying daily consumption of both items by 7.

$\text{Total weekly consumption of oats and water}=7*(464+192)\text{ deciliters}$

$\text{Total weekly consumption of oats and water}=7*(656)\text{ deciliters}$

$\text{Total weekly consumption of oats and water}=4592\text{ deciliters}$

Let us convert weekly consumption of water and oats into liters.

$\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10\frac{\text{ deciliters}}{\text{liter}}}$

$\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10}\cdot\frac{\text{ liters}}{\text{ deciliters}}}$

$\text{Total weekly consumption of oats and water}=\frac{4592}{10}\text{ liters}$

$\text{Total weekly consumption of oats and water}=459.2\text{ liters}$

Therefore, total weekly combined consumption of oats and water is 459.2 liters.

5 0

3 years ago

Read 2 more answers

A plastic bin contains red, yellow, and green key chains. Out of 350 key chains, 10% percent are yellow. Of the remaining key ch

Ulleksa [173]

Hello there! Thank you for asking your question here at Brainly! I will be assisting you with answering this question, and will be teaching you how to handle it on your own in the future.

We have 350 total keychains, in which 10% are yellow, 3/5 are green, and x are red. We will be solving for red, but we need to subtract 10% and 3/5 from 350.

So, let's find out how much 10% of 350 is.
Since 10% is equivalent to 1/10, we can divide 350 by 10 to find how many yellow key chains there are.
350 / 10 = 35.
There are 35 yellow key chains. We can subtract this from 350 to narrow it down.
350 - 35 = 315.

Now, let's find how much 3/5 of 350 is, and subtract it from our new number (315).

Divide 350 by 5, and then multiply that quotient by 3.
350 / 5 = 70.
70 x 3 = 210.

We have 210 green key chains. Now let's subtract that from 315. This will give us the remaining key chains - which are red.
315 - 210 = 105.

There are 105 red key chains.

I hope this helps!

3 0

3 years ago

What is the relationship between mass gravity and weight

Anastaziya [24]

Weight = mass * acceleration of gravity

6 0

3 years ago

Any one know how to find the roots of an equation?

soldier1979 [14.2K]

So what you do is
make into ax^2+bx+c=0 form

add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x= $\frac{-(-2)+/- \sqrt{(-2)^{2}-4(1)(9/2)} }{2(1)}$
x= $\frac{2+/- \sqrt{4-(36/2)} }{2}$
x= $\frac{2+/- \sqrt{4-(18)} }{2}$
x= $\frac{2+/- \sqrt{-14} }{2}$
x= $\frac{2+/- \sqrt{-14} }{2}$
x= $1+/- \frac{\sqrt{-14} }{2}$
x= $1+/- \frac{\sqrt{14} \sqrt{-1}}{2}$
x= $1+/- \frac{\sqrt{14} i }{2}$
x= $1+/- \frac{ i \sqrt{14} }{2}$

answer is C

6 0

3 years ago

What are the dimensions of a storage tank

motikmotik

Answer:

Step-by-step explanation:

550 48 6-0 3/16 3/16 800

1000 48 10-10 3/16 3/16 1300

1100 48 11-11 3/16 3/16 1400

1500 48 15-8 3/16 3/16 1650

65 9-0 3/16 3/16 1500

2000 65 11-10 3/16 3/16 2050

2500 65 14-10 3/16 3/16 2275

3000 65 17-8 3/16 3/16 2940

4000 65 23-8 3/16 3/16 3600

5000 72 23-8 1/4 1/4 5800

84 17-8 1/4 1/4 5400

7500 84 26-6 1/4 1/4 7150

96 19-8 1/4 1/4 6400

10000 96 26-6 1/4 5/16 8540

120 17-0 1/4 5/16 8100

12000 96 31-6 1/4 5/16 10500

120 20-8 1/4 5/16 9500

15000 108 31-6 5/16 5/16 13300

120 25-6 5/16 5/16 12150

20000 120 34-6 5/16 5/16 15500

25000 120 42-6 3/8 3/8 22300

30000 120 51-3 3/8 3/8 28000

4 0

3 years ago