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nlexa [21]
2 years ago
8

The square below represents one whole.

Mathematics
1 answer:
grandymaker [24]2 years ago
6 0

Answer:

Fraction: 81/100

Decimal: 0.81

Percentage: 81%

Step-by-step explanation:

The question is complete but the diagram mentioned can be found in

brainly.com/question/12188410

First step is to find the area of the whole square and then the area of the part that was shaded.

From the diagram, there are 100 squares in the whole square. 81 of those squares are shaded.

Area of the whole square = 10 by 10

= 10×10 = 100unit²

Area of shaded region = (10 by 8) + 1

= 80+1 = 81unit²

shaded area expressed as a fraction = 81unit²/100unit²

= 81/100

Shaded area expressed as a decimal = 81/100

You take the number 81 and carry the point by two decimal place from the right

= 0.81

Shaded area expressed as a percent of the whole = (81/100) × 100

= (81×100)/100

= 81%

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3 years ago
Suppose x, y, and z are all rational numbers. Is
umka2103 [35]
Yes number 1 yes yes
7 0
3 years ago
Find X. Round to the nearest tenth if necessary.
storchak [24]

Answer:

3.2

Step-by-step explanation:

If there are 2 secont lines intersecting inside a circle like the picture shown, then the theorem tells us that <em>"the product of 2 segments of one secant line is equal to the product of 2 segments of other secant line"</em>

<em></em>

Thus, we can say that:

x * 10 = 8 * 4

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x = 32/10

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3 0
3 years ago
PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
What is the approximate area of a circle with a radius of 10 in?
yKpoI14uk [10]

<em></em>\huge\boxed{\textsf{A.}\ 78.5\ \text{in}^2}

<em></em>

<em>Correction to your question text: diameter, not radius.</em>

The area of a circle is given by:

A=\pi r^2

The radius is half of the diameter.

A=\pi\cdot\left(\dfrac{10}{2}\right)^2

Substitute and solve.

\begin{aligned}A&=\pi\cdot\left(\frac{10}{2}\right)^2\\&=\pi\cdot5^2\\&=\pi\cdot25\\&\approx\boxed{78.5}\end{aligned}

5 0
1 year ago
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