ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

5 0

Answer:

Step-by-step explanation:

Starting with the first part, shifting 2 units left, this means that for this new function, for each value of x, the original function is equal to if you plugged in a value 2 values higher. Therefore, we should be looking for a x+2 -- that's C. Then, for the second part, we need to go up 9 units, which adds 9, so C fits that as well.

meriva3 years ago

3 0

Answer:

Step-by-step explanation:

Ok, we are first asked to shift two units to the left. This means that, each value of x compared to the original function is going to be two values higher. This means that, we are looking for x + 2 which can be seen in the answer C.

Ok, now we need to look for a nine unit shift up. This means that you add nine to the function. This can also be seen in the answer C.

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Suck at fractions and simplifying

galina1969 [7]

Answer:

Step-by-step explanation:

2(3) + 6²/6

Multiply 2x3 and 6² is just multiplying 6x6

6+36/6

Add 6+36

42/6

Divide 42 by 6

8 0

2 years ago

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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Anit [1.1K]

Well the area of a trapezoid is defined by the following formula:
A = $\frac{1}{2}(b_{1} + b_{2})h$ where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.

Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A = $\frac{1}{2} (15+25)(7)=140$

This is in square units of measure of course, so 140 in²

8 0

3 years ago

Use the drawing tool(s) to form the correct answer on the provided graph.

Dominik [7]

Answer:

see below. The solution is the doubly-shaded area.

Step-by-step explanation:

Each boundary line will be dashed, because the "or equal to" case is <em>not included</em>. Each shaded area will be above the corresponding boundary line because the comparison symbol is y > .... That is, only y-values greater than (above) those in the boundary line are part of the solution.

Of course, the boundary lines are graphed in the usual way. Each crosses the y-axis at the value of the constant in its equation. Each has a slope (rise/run) that is the value of the x-coefficient in the equation.