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mina [271]
3 years ago
7

Find all the powers of 3 that are in the range 3 through 1,000.

Mathematics
2 answers:
Roman55 [17]3 years ago
8 0
3 to the first is 3
3 to the second is 9
3 to the third is 27
3 to the fourth is 81
3 to the fifth is 243
3 to the sixth is 729
AlekseyPX3 years ago
7 0
3 9 27 81 243 729 are all the powers of 3 that are in the range 3 through 1,000
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Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
What is. 9 divided by 204
gulaghasi [49]
Is that .9?  or was that period mark accidental?
8 0
3 years ago
40
prohojiy [21]
The area of the trapezoid is 30

6 0
2 years ago
Sara opens a bank account with $200. The account accrues 2% interest compounded annually.
AleksAgata [21]
<span>A=P(1+rn)nt
A=200(1+.02)^3
A=200(1.02)^3
A=200(1.061208)
A=</span><span>212.2416
which u round to 212.24</span>
5 0
3 years ago
The figure below shows a shaded rectangle inside a large rectangle:
trasher [3.6K]

Answer:

46% i hope this helps

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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