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Dafna11 [192]
3 years ago
9

Pls very important!​ its due tomorrow

Mathematics
1 answer:
Rasek [7]3 years ago
6 0

Answer:

2,500 because 10,000 divided by 4 is 2,500

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Write the written form of the following expressions given in the symbolic form, then simplify each expression.
miss Akunina [59]

The values of the equation will be:

9. 12x - 1

10. -50 - x

11. -x + 14

12. x³ - 4y - 4

13. 8 - 6x

14. 288 - 1080x

15. 420 - y

16. 66 + 7y - 9x

<h3>How to compute the equation?</h3>

9. 4(3x+ 2) - 9

12x + 8 - 9

12x - 1

10. √144 – (62 –x)

12 - (62 - x)

-50 - x

11. (28 ÷ 4) – (x + 7)

7 - x + 7

= -x + 14

12. x³ – 4y - (6 + 2)

x³ - 4y - 4

13. 64 ÷ 8) – (x • 6)

= 8 - 6x

14. 72 (4 - 15x)

288 - 1080x

15. 4(√144 + 93)–y

4(12 + 93) - y

= 420 - y

16. 54 + 7y – (8 + 9x)

= 66 + 7y - 9x

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

4 0
2 years ago
What is 1/12(3a-6b)=? And why
Ipatiy [6.2K]

   3a - 6b  =   3 • (a - 2b)<span> =
a-2b/4</span>
5 0
3 years ago
Read 2 more answers
Which of the following choices shows y = (x − 3)^2 − 25 in standard form?
Ksivusya [100]
The answer would be x^2-6x-16

Explanation:
y=(x-3)^2 -25
(x-3)(x-3)-25
x^2-3x-3x+9-25
x^2-6x-16
6 0
2 years ago
(a)at davidson's bike rentals, it costs $14 to rent a bike for 3 hours. how many dollars does it cost per hour of bike use?
Elanso [62]
It costs about $4.66
5 0
3 years ago
Using the extended Euclidean algorithm, find the multiplicative inverse of a. 1234 mod 4321 b. 24140 mod 40902
horsena [70]

(a) The inverse of 1234 (mod 4321) is x such that 1234*x ≡ 1 (mod 4321). Apply Euclid's algorithm:

4321 = 1234 * 3 + 619

1234 = 619 * 1 + 615

619 = 615 * 1 + 4

615 = 4 * 153 + 3

4 = 3 * 1 + 1

Now write 1 as a linear combination of 4321 and 1234:

1 = 4 - 3

1 = 4 - (615 - 4 * 153) = 4 * 154 - 615

1 = 619 * 154 - 155 * (1234 - 619) = 619 * 309 - 155 * 1234

1 = (4321 - 1234 * 3) * 309 - 155 * 1234 = 4321 * 309 - 1082 * 1234

Reducing this leaves us with

1 ≡ -1082 * 1234 (mod 4321)

and so the inverse is

-1082 ≡ 3239 (mod 4321)

(b) Both 24140 and 40902 are even, so there GCD can't possibly be 1 and there is no inverse.

8 0
3 years ago
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