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Sladkaya [172]
3 years ago
6

The diagram shows a rectangular yard. Each small block is

Mathematics
1 answer:
valina [46]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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I need help on a question
schepotkina [342]

Given the figure of a regular pyramid

The base of the pyramid is a hexagon with a side length = 6

The lateral area is 6 times the area of one of the side triangles

So, the side triangle has a base = 6

The height will be:

\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}

so, the lateral area =

6\cdot\frac{1}{2}\cdot6\cdot\sqrt[]{63}=18\sqrt[]{63}

3 0
1 year ago
What is the midpoint of -5,2 and 1,5
ANEK [815]

Answer:(-2,3.5)

Step-by-step explanation: Add the endpoints and divide by two for the x-values and the y-values

4 0
3 years ago
Given vector u, what is the magnitude, |u|, and directional angle, θ, in standard position?
Dominik [7]

The magnitude of a vector has to do with the vector length that is used to show the initial and final position of the vector.

<h3>What is a Vector?</h3>

This refers to the quantity that has a magnitude and direction and can be used to show position.

Hence, we can see that the vector, magnitude, and the directional angle values are not given so a general overview was given.

Read more about vectors here:

brainly.com/question/25811261

#SPJ1

5 0
2 years ago
Read 2 more answers
The data table represents the distance between a well-known lighthouse and a cruise ship over time. The cruise ship is travellin
Trava [24]
Find the velocity first, the "slope".

m=(y2-y1)/(x2-x1)

m=(95.5-53)/(4-2)

m=21.25  ?  Your equations are wrong, I'll double check with another set of points...

m=(350.5-308)/(16-14)

m=21.25  LOL, yep none of your lines has the correct slope.

Anyway...

y=21.25x+b, using any point we can solve for the y-intercept, or "b", (2, 53)

53=21.25(2)+b

53=42.5+b

10.5=b so the distance to the lighthouse as a function of time is:

y=21.25x+10.5

So essentially, you should fire your teacher or burn that book you are using :)

6 0
4 years ago
Read 2 more answers
Of the dogs at the dog show,
Olin [163]
So, let's say that all the dogs had a number of x.

then 1/12 x were the Hound Group dogs.

then, out of the Hound Group,, that is 1/12 x, 3/10 were English Foxhounds.

For this, we need to multiply the fractions:

\frac{1}{12}x* \frac{3}{10} = \frac{3}{120}x =\frac{1}{40}x

so of all the dogs at the show, the English Foxhunds were a 1/40 fraction,  
5 0
3 years ago
Read 2 more answers
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