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DENIUS [597]
3 years ago
6

A chocolatier makes 1,313 chocolate covered strawberries per day. The strawberries are packed into boxes. A large box contains 9

strawberries and a small box contains 4 strawberries. If the large boxes are filled first, how many small boxes are needed?
Mathematics
1 answer:
kaheart [24]3 years ago
6 0

Answer:

2 small boxes

Step-by-step explanation:

The chocolatier makes 1313 chocolate covered strawberries.

The large boxes contains 9 strawberries and the small box contains 4 strawberries.

The large boxes are filled first.

We need to divide 1313 by 9 and find the remainder.

1313 / 9 = 145 remainder 8

This means that 145 large boxes will be needed and 8 strawberries will be left.

The number of small boxes needed is therefore:

8 / 4 = 2 boxes

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Answer:

30% constituents=20 mL

10% constituents=180 mL

Step-by-step explanation:

x= 30% volume

y=10% volume

For our first equation, we know the total volume is 200 mL and is the sum

x+y=200

y=200-x (1)

For our second equation, we do a mass balance for 200 mL of final solution.

12% w/v = 0.12 g/mL

This means that in 1 mL of solution, we have 0.12 g of NaCl.

For any solution, concentration multiplied by volume will give the mass of NaCl:

Mass in x mL= C*V (g/mL) (mL)

So in 200 mL, we have

0.12*200 (g/mL) (mL)

=24g of NaCl

Cx*Vx + Cy*Vy=24

0.3x+0.1y=24 (2)

Substitute y=200-x into (2)

0.3x+0.1(200-x)=24

0.3x+20-0.1x=24

0.2x=24-20

0.2x=4

Divide both sides by 0.2

0.2x/0.2=4/0.2

x=20

Substitute x=20 into (1)

y=200-x

y=200-20

y=180

30% constituents=20 mL

10% constituents=180 mL

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