You spin a spinner with 8 equally likely spaces numbered 1 to 8. Event A is the

Mathematics

1 answer:

jenyasd209 [6]3 years ago

3 0

Answer:

A spinner has equal sections numbered 1-8. If you spin the spinner once, what is the probability that you will not get a 5? | Socratic A spinner has equal sections numbered 1-8. If you spin the spinner once, what is the probability that you will not get a 5?

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A sphere has a surface area of about 999 square millimeters. What is the radius, in millimeters, of the sphere

motikmotik

Given that, a sphere has a surface area of about 999 square millimeters.

Formula to find the surface area of sphere is,

S= 4πr² Where r = radius of the sphere and S= surface area.

Given S= 999 square millimeters.

So, we can write:

4πr² = 999

4 * 3.14 * r² = 999 Since, π = 3.14

12.56 *r² = 999

$r^2=\frac{999}{12.56}$ Divide each sides by 12.56.

r² = 79.53821656

r = √79.53821656 Taking square root to each sides of equation.

r = 8.918420071

So, r = 8.918 Rounded to nearest thousandth.

So, radius of the sphere is 8.918 millimeters.

Hope this helps you!

5 0

3 years ago

Find the sum of a finite geometric sequence from n=1 to n=8, using the expression -2(3)^n-1

MissTica

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}
\end{cases}
\\\\\\
\sum\limits_{n=1}^{8}~-2(3)^{n-1}~~
\begin{cases}
n=8\\
a_1=-2\\
r=3
\end{cases}\implies S_8=-2\left( \cfrac{1-3^8}{1-3} \right)
\\\\\\
S_8=\underline{-2}\left( \cfrac{1-6561}{\underline{-2}} \right)\implies s_8=1-6561\implies S_8=-6560$