If it is isosceles, than the legs are the same. We will call them X. The formula for the area of a triangle is 1/2 (base * height). But the base and the height are both X. So the area (18) is equal to 1/2 (x * x), or 1/2(x^2). This means that 36 = x^2. Thus, the length of each side is 6 inches. You can check this work by plugging those into the formula for area. You will find that it equals 18.
Answer:
17.84
Step-by-step explanation:
2.23
8 x
-----------
17.84
Answer: 336 sq ft
Step-by-step explanation: what is it even asking?

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.