The product of two fractions is 14/9.Write all possible answers

Plsss help no one answered the other times I put this question

svetlana [45]

Answer:

a) The equation (10s + 8w) represents the calories Bridget ate on Monday and the equation (20s + w) represents the calories she ate the next day.

b) The number of calories in each strawberry is 4 and the number of calories in each vanilla wafer cookie is 19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is s and the number of calories in a vanilla wafer cookie is w , the number of calories Bridget ate on Monday is 10s + 8w. The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s + w.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

7 0

3 years ago

Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct

Nana76 [90]

Answer:

$Fx=\frac{5\pm\sqrt{25+24} }{6}$

Step-by-step explanation:

A quadratic equation in one variable given by the general expression:

$ax^2+bx+c$

Where:

$a\neq 0$

The roots of this equation can be found using the quadratic formula, which is given by:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

So:

$y(x)=3x^2-5x-2=0$

As you can see, in this case:

$a=3\\b=-5\\c=-2$

Using the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}$

Therefore, the answer is:

$Fx=\frac{5\pm\sqrt{25+24} }{6}$

4 0

3 years ago

I am so dumb and lazy to do this help plz for 15 points

Afina-wow [57]

Isn’t it the example part?

5 0

3 years ago

Need help plsssssss :(

ahrayia [7]

Supplementary angle must add up to 180 so the supplement will be 108 degrees. 180-72=108.

5 0

3 years ago

What is the inverse of the function f(x) = one-quarterx – 12?

zzz [600]

Hey there! :)

Answer:

y = 4x + 48

Step-by-step explanation:

Original equation:

y = 1/4x -12

Switch 'x' and 'y' to solve for the inverse:

x = 1/4y - 12

Add 12 to both sides:

x + 12 = 1/4y - 12 + 12

x + 12 = 1/4y

Multiply both sides by 4:

4(x+12) = y

4x + 48 = y

The inverse is y = 4x + 48

6 0

3 years ago

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