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zzz [600]
3 years ago
6

Equation: Y=2/3x+0.25

Mathematics
1 answer:
Llana [10]3 years ago
5 0

Answer:

Based on this equation the number of wins for a team that scores 2 goals per match is 1.6

Step-by-step explanation:

From the information given

{\displaystyle y =  \frac{2}{3} (2) + 0.25  = \frac{4}{3} + \frac{1}{4} = \frac{19}{12} = 1.58333 = 1.6

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A ladder of length 2x+1 feet is positioned against a wall such that bottom is x-1 feet away from a wall. The distance between th
Natali5045456 [20]
So leangh of ladder=2x+1

bottom edgre=x-1
wall edge=2x

so therefor, since this is a right triangle, use pythagorean theorem
a^2+b^2=c^2
c=hypotonues=longest side
b and a=sides touching the right angle

so x-1 and 2x are a and b
2x+1=c

subsitute
(x-1)^2+(2x)^2=(2x+1)^2
x^2-2x+1+4x^2=4x^2+4x+1
add like terms
5x^2-2x+1=4x^2+4x+1
subtract 1 from both sdies
5x^2-2x=4x^2+4x
subtract 4x from both sdies
5x^2-6x=4x^2
subtract 4x^2 from both sides
x^2-6x =0
factor out the x using distributive property which is
ab+ac=a(b+c)
x^2-6x=x(x-6)
(x)(x-6)=0

if xy=0 then assume x and/or y=0
x=0
we remember that one of the side legnths is 2x and if x=0 then the side legnth=0 which is not possible, so we discard

x-6=0
add 6 to both sides
x=6

subsitute and solve


legnth of ladder=2x+1
x=6 subsitute
2(6)+1=12+1=13
legnth of ladder =13 feet

height=2x
2(6)=12
height=12 feet

base=x-1
6-1=5



legnth of ladder=13 feet
height=12 feet
base=5 feet
6 0
3 years ago
Read 2 more answers
Which best describes the value of 7 in 2.173?
kati45 [8]

Answer:

I'm guessing they mean the place? If it is, then it's the "hundredths" place

4 0
3 years ago
Problem:
Molodets [167]

Answer:

a)

We know that:

a, b > 0

a < b

With this, we want to prove that a^2 < b^2

Well, we start with:

a < b

If we multiply both sides by a, we get:

a*a < b*a

a^2 < b*a

now let's go back to the initial inequality.

a < b

if we now multiply both sides by b, we get:

a*b < b*b

a*b < b^2

Then we have the two inequalities:

a^2 < b*a

a*b < b^2

a*b = b*a

Then we can rewrite this as:

a^2 < b*a < b^2

This means that:

a^2 < b^2

b) Now we know that a.b > 0, and a^2 < b^2

With this, we want to prove that a < b

So let's start with:

a^2 < b^2

only with this, we can know that a*b will be between these two numbers.

Then:

a^2 < a*b < b^2

Now just divide all the sides by a or b.

if we divide all of them by a, we get:

a^2/a < a*b/a < b^2/a

a < b < b^2/a

In the first part, we have a < b, this is what we wanted to get.

Another way can be:

a^2 < b^2

divide both sides by a^2

1 < b^2/a^2

Let's apply the square root in both sides:

√1 < √( b^2/a^2)

1 < b/a

Now we multiply both sides by a:

a < b

7 0
3 years ago
Given that F(x) = x 2 + 2, evaluate F(1) + F(5).
Igoryamba

Answer:

F(1)= (1)2 + 2

          2+2

           =4

F(5)= (5)2 + 2

          10+2

           =12

F(1) + F(5) = 12+4

            =16

Step-by-step explanation:

:D

8 0
3 years ago
Someone please help me!!!
Allushta [10]
What do you want people to help you answer your quesion
7 0
4 years ago
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