Equation: Y=2/3x+0.25
1 answer:
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Check the picture below.
I'd like to point out, is 1:5 from R to T, since that matters, that way we know the ratio from RS is the 1 and the ratio ST is the 5.
I'd like to point out, is 1:5 from R to T, since that matters, that way we know the ratio from RS is the 1 and the ratio ST is the 5.
9514 1404 393
Answer:
256 feet
Step-by-step explanation:
The vertex of the quadratic ax^2 +bx +c is found at x=-b/(2a). This means the time at which the rocket reaches it maximum height is ...
t = -128/(2(-16)) = 4 . . . . seconds
Evaluating h at t=4 gives the maximum height:
h = -16(4^2) +128(4) = -256 +512 = 256
The maximum height of the rocket is 256 feet.
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If you can read this value from "the graph at the left," you can save yourself some computation.
