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Andreas93 [3]
3 years ago
6

How manymore batteries do 6 flashlights need than4 flashlights? Explain.​

Mathematics
2 answers:
Bogdan [553]3 years ago
8 0

Answer:

it depends on the flash light big flashlights take 2 big batteries and little ones take 1 and even some you haft to charge.

krok68 [10]3 years ago
6 0

Step-by-step explanation:

If there are two batteries in each flashlight in 4 flashlights there are 8 batteries total. This is because two batteries times 4 flashlights equals 8 batteries total. In 6 flashlights with 2 batteries in each one multiply 6 flashlights by 2 batteries to get 12 batteries total. So in 4 flashlight there is 8 batteries total and in 6 flashlights there is 12 total batteries. 12 batteries-8 batteries=4 batteries. 6 flashlights require 4 more batteries than 4 flashlights.

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3 years ago
1. Which of the following is equivalent to x5y2/xy2 when x ≠ 0 and y ≠ 0?
Sedaia [141]
Q1. The answer is <span>D. x4
</span>
Let's first rewrite the expression:
x⁵y²/xy² = x⁵/x * y²/y²

Using the rule xᵃ/xᵇ = x(ᵃ⁻ᵇ), we can write the expression as following:
x⁵y²/xy² = x⁵/x * y²/y² = x⁵⁻¹ * y²⁻² = x⁴ * y⁰ = x⁴ * 1 = x⁴

Thus, the correct answer is D.


Q2. The answer is <span>A. 5(5^3/2/5)^2
</span>
125 in the form of exponent is 5³.
125 = 5³
Now, let's calculate all choices. 
 
The rules we will use are:
xᵃ * xᵇ = x(ᵃ⁺ᵇ)
xᵃ/xᵇ = x(ᵃ⁻ᵇ)
(xᵃ)ᵇ = xᵃ*ᵇ

A. 5(5³/2/5)² = 5 * (5³ * 5/2)²
                      = 5 * (5³⁺¹/2)²
                      = 5 * (5⁴/2)²
                      = 5 * (5⁴)²/(2)²
                      = 5 * 5⁴*²/4
                      = 5 * 5⁸ / 4
                      = 5¹⁺⁸ / 4
                      = 5⁹/4
                      ≠ 5³ ≠ 125

B. (5³/5⁴)⁻³ = (5³⁻⁴)⁻³
                   = (5⁻¹)⁻³
                   = 5⁽⁻¹⁾*⁽⁻³⁾
                   = 5³
                   = 125

C. 5⁻²/5⁻⁵  = 5⁽⁻²⁾⁻⁽⁻⁵) 
                  = 5⁽⁻²⁾⁺⁵
                  = 5³
                  = 125<span>

D. 5(5</span>⁵/5³) = 5 * 5⁵⁻³
                  = 5 * 5²
                  = 5¹⁺²
                  = 5³
                  = 125

Therefore, the only expression that is not equal to 125 is A.


Q3. The answer is <span>63x5

Let's check all choices
</span>The rules we will use are:
xᵃ * xᵇ = x(ᵃ⁺ᵇ)
xᵃ/xᵇ = x(ᵃ⁻ᵇ)
(xᵃ)ᵇ = xᵃ*ᵇ

A. 6³<span>x 
</span>6³x/6x⁵ = 6³/6 * x/x⁵
             = 6³⁻¹ * x¹⁻⁵
             = 6²x⁻⁴
             = 36x⁻⁴
             ≠ 36<span>

B. 6</span>³x⁵
6³x⁵/6x⁵ = 6³/6 * x⁵/x⁵
              = 6³⁻¹ * x⁵⁻⁵
              = 6² * x⁰
<span>              = 36 * 1
              = 36

C. 6x</span>⁵<span> 
</span>6x⁵/6x⁵ = 1
             ≠ 36
<span>
D. 6</span>⁷x⁵
6⁷x⁵/6x⁵ = 6⁷/6 * x⁵/x⁵
              = 6⁷⁻¹ * x⁵⁻⁵
              = 6⁶ * x⁰
              = 46656 * 1
              ≠ 36

Therefore, the correct choice is B.


Q4. The answer is

We will use the rule: xᵃ/xᵇ = x(ᵃ⁻ᵇ)

5.4 x 10¹²/1.2 x 10³ = 5.4 / 1.2 x 10¹²/10³
                               = 4.5 x 10¹²⁻³
                               = 4.5 x 10⁹


Q5. The answer is B. <span>To subtract powers with the same base, divide the exponents

Some of the rules </span><span>regarding operations with exponents are:
</span>xᵃ/xᵇ = x(ᵃ⁻ᵇ) - choice A
xᵃ * xᵇ = x(ᵃ⁺ᵇ) - choice C
(xᵃ)ᵇ = xᵃ*ᵇ - choice D

Through the process of elimination, choice B is not true.
8 0
3 years ago
Read 2 more answers
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