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krek1111 [17]
3 years ago
7

What is the predicted order of first ionization energies from highest to lowest for lithium (Li), sodium (Na), potassium (K), an

d rubidium (Rb)?
Rb > K > Na > Li
K > Rb > Na > Li
Li > Na > K > Rb
Rb > K > Li > Na
Chemistry
2 answers:
xz_007 [3.2K]3 years ago
6 0

Answer:

Li>Na>K>Rb

Explanation:

natima [27]3 years ago
5 0

Answer:

Rb > K > Na > Li

Explanation:

Ionization energy increases up the period and up the group.

From the periodic table, we can see that Li is the going to have the highest ionization energy and Rb is going to have the lowest.

Therefore, the correct answer is the first choice

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True or False:
lesya [120]

Answer:

False

Explanation:

  • Mendeleev was the first scientist to arrange the element in such a periodic order but there was a mistake that he arranged in increasing order of mass.
  • Today we use the periodic table given by Henry Mosley where atomic no is first priority
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2 years ago
Explain hydrophobic and hydrophylic​
Alika [10]

Answer:

Something defined as hydrophilic is actually attracted to water, while something that is hydrophobic resists water.

Explanation:

I hope it's help u :)

5 0
3 years ago
Read 2 more answers
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alina1380 [7]

Answer:

1st page, number a-ENergy is added or absorbed

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Explanation:

8 0
3 years ago
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A student prepares a aqueous solution of butanoic acid . Calculate the fraction of butanoic acid that is in the dissociated form
ella [17]

Answer:

15.4%

Explanation:

If Ka = 0.54 mM = 1.51x10⁻⁵

Then;

C₄H₈O₂               -------->            C₄H₇O₂⁻          +           H⁺

I                    0.54x10⁻³                             0                                0

E                   0.54x10⁻³(1-x)                      0.54x10⁻³x                0.54x10⁻³x

Recall that x is the percentage degree of dissociation

From the ICE table;

Ka = [C₄H₇O₂⁻] [ H⁺]/[C₄H₈O₂]

1.51x10⁻⁵=(0.54x10⁻³x) (0.54x10⁻³x)/ 0.54x10⁻³(1-x)  

1.51x10⁻⁵ = 0.54x10⁻³x^2/1-x

1.51x10⁻⁵(1-x) = 0.54x10⁻³x^2

1.51x10⁻⁵ - 1.51x10⁻⁵x = 0.54x10⁻³x^2

Hence;

0.54x10⁻³x^2 + 1.51x10⁻⁵x - 1.51x10⁻⁵=0

x^2 + 0.028x - 0.028 = 0

Solving the quadratic equation here;

x = 0.154 or −0.182

Ignoring the negative result, x = 0.154

Hence, fraction of butanoic acid that is in the dissociated form in this solution = 15.4%

3 0
3 years ago
For the following nuclear reaction, what was the beginning radionuclide (X)? X → 86Rn222 + 2He4
BigorU [14]
The original radioisotope underwent double-alpha decay, where the original nucleus lost a total of 4 protons and 4 neutrons.

The original radioisotope would have an atomic number of 86+4 (protons), and would have an atomic mass of 222+8 (protons + neutrons). This would make the element Thorium-230, or 90Th230.
3 0
3 years ago
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