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krek1111 [17]
4 years ago
7

What is the predicted order of first ionization energies from highest to lowest for lithium (Li), sodium (Na), potassium (K), an

d rubidium (Rb)?
Rb > K > Na > Li
K > Rb > Na > Li
Li > Na > K > Rb
Rb > K > Li > Na
Chemistry
2 answers:
xz_007 [3.2K]4 years ago
6 0

Answer:

Li>Na>K>Rb

Explanation:

natima [27]4 years ago
5 0

Answer:

Rb > K > Na > Li

Explanation:

Ionization energy increases up the period and up the group.

From the periodic table, we can see that Li is the going to have the highest ionization energy and Rb is going to have the lowest.

Therefore, the correct answer is the first choice

You might be interested in
Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
coldgirl [10]

Answer :

a. The oxidizing agent is: BH_4^-

b. The reducing agent is: ClO_3^-

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : BH_4^-\rightarrow H_2BO_3^-

Reduction : ClO_3^-\rightarrow Cl^-

Now balance oxygen atom on both side.

Oxidation : BH_4^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-  

Now balance hydrogen atom on both side.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-

Now balance the charge.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-

Reduction : ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-

In order to balance the electrons, we multiply the oxidation reaction by 6 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-

Reduction : 4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-

The balanced chemical equation in acidic medium will be,

6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-

3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-

In the redox reaction, ClO_3^- act as oxidizing agent and BH_4^- act as an reducing agent.

7 0
3 years ago
5
Rufina [12.5K]

Answer:

massive flooding occurs in may at this location

Explanation:

i did the quiz idk if its right though :/

5 0
4 years ago
A carbon nanoparticle (very small particle) contains 8000 carbon atoms. According to the Einstein model of a solid, how many osc
Rudiy27

Answer:

24000

Explanation:

Given that:

The numbers of carbon atoms = 8000

According to the Einstein model of solid;

Einstein’s model assumes that each atom of the solid vibrates around its position of equilibrium independently of the other atoms (which amounts to neglecting the interactions between particles.

Number of oscillators = 3(8000)

Number of oscillators = 24000

5 0
3 years ago
molecules with a plane of symmetry between the chiral centers are achiral and meso. identify which of the following molecules ar
maks197457 [2]

Molecules with a plane of symmetry between the chiral centers are achiral and meso. From the given molecules (Picture attached) only (A) compound 1 is meso.

When compounds possess a plane of symmetry between the chiral centers they are called achiral or meso compounds. Among the given compounds (A) compound 1 have a plane of symmetry. So we can say compound one is a meso or achiral compound. Compounds two, three, and four have no plane of symmetry, as you can see in the structures attached. So all other compounds (compound 2, compound 3, and compound 4) except compound one are not meso or achiral.

You can also learn about meso compounds from the following question:

brainly.com/question/29022658

#SPJ4

7 0
1 year ago
How is atomic number and mass related to protons, neutrons, & electrons?
artcher [175]
The atomic number is the numbers of protons

6 0
4 years ago
Read 2 more answers
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