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Alex Ar [27]
3 years ago
14

A strontium-90 atom that has lost 2 electrons has ________ protons, ________ neutrons, and ________ electrons.

Chemistry
2 answers:
svetlana [45]3 years ago
5 0

For an atom, the atomic number is equal to number of protons and number of electrons. Mass number is sum of number of protons and neutrons in nucleus of an atom. Atomic number is denoted by symbol Z and mass number is denoted by symbol A.

The atomic number of strontium is Z=38 and mass number is A=90.

Now, Z=n_{p}=n_{e}=38

Also, A=n_{p}+n_{n}=90

Putting the value of n_{p} in above equation,

A=38+n_{n}=90

Or,

n_{n}=90-38=52

Thus, number of neutrons are 52.

Now, after losing two electrons, number of protons and neutrons remains the same but number of electrons becomes 38-2=36

Therefore, a strontium-90 atom that has lost 2 electrons has <u>38</u> protons, <u>52</u> neutrons and <u>36</u> electrons.

Sliva [168]3 years ago
4 0
An atom of strontium-90 contains how many electrons, protons, and neutrons?
38e⁻, 38 protons, and 52 neutrons
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If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
kodGreya [7K]

Answer:

[Cu^{2+}]=0.041 M

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

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6 0
3 years ago
calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units
cricket20 [7]

Answer:

21.2 gm

Explanation:

calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units

butane is the hydrocarbon C4H10  

in combustion, we react hydrocarbons with O2 to form CO2 and H2O

so

C4H10  + O2---------------->  CO2 + H2O

BALANCE

2C4H10 + 1302--------> 8CO2 + 10 H2O

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64.1 gm of CO2 is

64.1/44 = 1.46 MOLES OF  CO2,

FOR EVERY 8 MOLES OF CO2 WE NEED 2 MOLES OF BUTANE  IT IS A

8:2 OR 4:1 RATIO.  THE MOLES OF C4H10 ARE 1/4 THE MOLES OF CO2

SO

THE MOLES OF C4H10 H10 ARE 1.46/4 =0.365 MOLES

THE MOLAR MASS OF BUTANE IS 58.12

0.365 MOLES OF C4H10 HAS A MASS OF 0.365 X 58.12 = 21.2 gm

6 0
3 years ago
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