As the temperature of a gas increases, the average kinetic energy of the gas particles increases and the average speed of a gas particle increases.
According to the kinetic theory of gases, all gases are made of microscopic molecules that move in straight lines until they bump into another gas molecule or object. This transfer of energy causes molecules to move around faster and bump into each other more.
Kinetic energy is proportional to the speed of the molecules. As the speed of the colliding molecules increases, so does the total kinetic energy of all the gas molecules. It's pretty difficult to measure the speed of an individual gas molecule.
Instead, temperature can be used as a measure of the average kinetic energy of all the molecules in the gas. As the gas molecules gain energy and move faster, the temperature goes up. This is why Amy feels warmer!
To determine the average kinetic energy of gas molecules, we need to know the temperature of the gas, the universal gas constant (R), and Avogadro's number (NA).
Learn more about kinetic theory of gases here : brainly.com/question/11067389
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Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point
elevation is directly proportional to the molality of the solution
according to the equation: ΔTb = Kb · b.<span>
ΔTb - the boiling point
elevation.
Kb - the ebullioscopic
constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
An earthquake's magnitude is a measure of how much energy an earthquake releases. Typically, the richter scale is used.
Answer:
E = 1.602v
Explanation:
Use the Nernst Equation => E(non-std) = E⁰(std) – (0.0592/n)logQc …
Zn⁰(s) => Zn⁺²(aq) + 2 eˉ
2Ag⁺(aq) + 2eˉ=> 2Ag⁰(s)
_____________________________
Zn⁰(s) + 2Ag⁺(aq) => Zn⁺²(aq) + 2Ag(s)
Given E⁰ = 1.562v
Qc = [Zn⁺²(aq)]/[Ag⁺]² = (1 x 10ˉ³)/(0.150)² = 0.044
E = E⁰ -(0.0592/n)logQc = 1.562v – (0.0592/2)log(0.044) = 1.602v