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3 years ago

Please help. 10 points and brainliest.(Ignore the already marked option)

Mathematics

1 answer:

Illusion [34]3 years ago

4 0

Answer:

Step-by-step explanation:

from 1-3:

2 values

from 4-6:

5 values

from 7-9:

3 values

from 10-12:

1 value

11 values total

the option that has all this is B

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Dori bought a sandwich for $6.75, a bag of dried fruit for $1.45 and a bottle of water for $1.75. She paid the cashier with a $2

Len [333]

Answer:

She would receive $10.05 cents back

Step-by-step explanation:

Add 6.75, 1.45, and 1.75. You would get 9.95. Then, you would subtract $20.00 by $9.95, getting 10.05 as change.

Hope this helps!

5 0

3 years ago

Find all the missing measurement

Marat540 [252]

Answer:

m = 28

Step-by-step explanation:

The two triangles are similar, therefore we can make proportions

36/24 = 42/m

m = 42(24)/36 = 28

5 0

3 years ago

In triangle PQR, Line QS and line SR are angle bisectors to angle P (74 degrees). How many Degrees are in the angle QSR.

AlexFokin [52]

we know that

in the triangle PQR

m∠PQR+m∠QPR+m∠QRP=180°------> the sum of the internal angles of a triangle is equal to 180 degrees

(m∠PQR+m∠QRP)+74°=180°-------> (m∠PQR+m∠QRP)=106°

we know that

If QS and SR are angle bisectors

then

In the triangle QSR

m∠SQR+m∠QSR+m∠QRS=180°-------> equation 1

and

(m∠SQR+m∠QRS)=106°/2--------> (m∠SQR+m∠QRS)=53°

substitute the value of (m∠SQR+m∠QRS)=53° in the equation 1

53°+m∠QSR=180°

m∠QSR=180°-53°-------->m∠QSR= 27°

therefore

the answer is

The measure of angle QSR is 27 degrees

4 0

4 years ago

The angle measurements in the diagram are represented by the following expressions. A=5x-5 B=3x+13

weeeeeb [17]

Answer:

Step-by-step explanation: 5x-5=3x+13---> 5x-3x=13+5---> 2x=13+5---- 2x=18----> x=9 hope it helps

3 0

3 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago