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Radda [10]
3 years ago
9

Find the value of x. Will mark brainliest.

Mathematics
2 answers:
Arlecino [84]3 years ago
4 0

Answer:

15

Step-by-step explanation:

Because this figure is a parallelogram, the diagonals bisect each other. This means that the diagonals cut each other perfectly in half, meaning that x and 15 have the same value. Hope this helps!

aliya0001 [1]3 years ago
3 0

Step-by-step explanation:

I think its 5 for x if you do 15/3=5 I think

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Peter wants to make for necklaces that are the same way. He asked his friends to cut the string for the necklace is 15 paper cli
postnew [5]

Correct question is;

Peter wants to make four necklaces that are the same way. He asked his friends to cut the string for the necklace 15 paper clips long. Would all the lengths be the same? Explain your think

Answer:

No, the lengths would not be the same. This is due to the fact the the paper clips could be in different sizes.

Step-by-step explanation:

We are told that he wants to make four necklaces that are the same way and that he told his friends to cut the string for the necklace 15 paper clips long.

Now, we are not told the sizes of the paper clips and we know that paper clips come in different sizes. Thus the paper clips in which the strings are cut could be in different sizes. Therefore, the lengths wouldn't be the same due to that.

5 0
2 years ago
Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to b
Alina [70]

Answer:

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 28.983051

Chi-square value = χ² = 2.154239

Degree of freedom = 1

Critical value = 3.841

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

Step-by-step explanation:

He frequently traps the moles and has noticed what appears to be a preference for a peanut butter-oatmeal mixture by the meadow voles vs apple slices are usually used in traps, where the common voles seem to prefer the apple slices.

So he conducted a study where he used a peanut butter-oatmeal mixture in half the traps and the normal apple slices in his remaining traps to see if there was a food preference between the two different voles.

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Data collected by Dr. Pagels:

                                              meadow voles     common voles      Row Total

apple slices                                     26                          32                      58

peanut butter-oatmeal                   35                          25                     60

Column Total                                   61                          57                     118

Where 118 is the grand total.

The expected number is given by

Expected = (row total)×(column total)/grand total

Expected meadow vole/apple slices = 58×61/118

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 58×57/118

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 60×61/118

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 60×57/118

Expected common vole/peanut butter-oatmeal = 28.983051

The chi-square statistic value is given by

χ² = Σ(Observed - Expected)²/Expected

χ² = (26 - 29.983051)²/29.983051 + (32 - 28.016949)²/28.016949 + (35 - 31.016949)²/31.016949 + (25 - 28.983051)²/28.983051

χ² = 2.154239

The degrees of freedom is given by

DoF = (row - 1)×(col - 1)

For the given case, we have 2 rows and 2 columns

DoF = (2 - 1)×(2 - 1)

DoF = 1

The given level of significance = 0.05

The critical value from the chi-square table at α = 0.05 and DoF = 1 is found to be

Critical value = 3.841

Conclusion:

Reject H₀ If χ² > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

For the given case,

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

8 0
3 years ago
The graph of a quadratic equation passes through
Katarina [22]

Answer:

2

Step-by-step explanation:

7 0
2 years ago
Write an equation for the line parallel to the given line that contains <br> C(4,8);y=-3x+4
Brrunno [24]
Parallel line means they have the same slope 
y = mx + b 
where m = slope 
y = -3 + 4
here the slope is negative 3
y = -3x + b
plug in (4, 8)
8 = -3(4) + b 
b = 8 + 12
b = 20

The answer is y = -3x + 20
6 0
3 years ago
A twin-engine airplane has a speed of 300 mi/hr in still air. Suppose this airplane heads directly south and encounters a 50 mi/
VashaNatasha [74]
Ummm i believe that its 250mph
4 0
3 years ago
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