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PolarNik [594]
2 years ago
11

I need help please thank you

Mathematics
1 answer:
Dafna11 [192]2 years ago
3 0

Answer:

See attachment

Step-by-step explanation:

We can graph this line using the equation given to us. The equation is in slope-intercept form, y=mx+b. In this form, m = slope and b = the y-intercept.

So, we can tell that the slope is -\frac{1}{5} and the y-intercept is (2,0).

We begin by plotting on the graph the y-intercept, (2,0).

The slope also equals the \frac{rise}{run}. The slope is negative, so the line will slope down. From the point we have plotted, we will <em>rise</em> negative 1 unit. This means to move down<em> </em>1 unit. From this point, we will <em>run</em> 5 units. Because the line is negative, we will move 5 units to the left, not the right. We land on point (5,1).

Now, we will draw a line from these two points. This is the line shown in the equation.

Good luck ^^

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A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq
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Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

s=16.6 represent the sample deviation

\bar X=12.8 represent the sample mean

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\alpha=1-0.99=0.01 represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

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We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

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We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

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