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ra1l [238]
3 years ago
10

Please help with this question

Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0

In a symmetric histogram, you have the same number of points to the left and to the right of the median. An example of this is the distribution {1,2,3,4,5}. We have 3 as the median and there are two items below the median (1,2) and two items above the median (4,5).

If we place another number into this distribution, say the number 5, then we have {1,2,3,4,5,5} and we no longer have symmetry. We can fix this by adding in 1 to get {1,1,2,3,4,5,5} and now we have symmetry again. Think of it like having a weight scale. If you add a coin on one side, then you have to add the same weight to the other side to keep balance.

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2x+12 would be the answer
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Step-by-step explanation:


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(Please look at the NUMBERS below the picture)
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7 0
2 years ago
A car was Skid to a half a uniform rate of -9.4 m/s ^2 squared if the measure skid marks that are 34 m long with what speed is t
babymother [125]

Answer:

vi = 25.28 m/s

Step-by-step explanation:

a = -9.4 m/s²

x = 34 m

vf = 0 m/s

vi = ?

We can apply the equation

vf² = vi² + 2*a*x

⇒     vi = √(vf² - 2*a*x)

⇒     vi = √((0 m/s)² - 2*(-9.4 m/s²)*34 m)

⇒     vi = 25.28 m/s

5 0
3 years ago
QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
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