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postnew [5]
2 years ago
8

If tan q= 0.09 and q is in quadrant 3, find the approximate value of cos q.

Mathematics
1 answer:
shusha [124]2 years ago
5 0

Answer: A

Step-by-step explanation:

 

h=   1

k=   4

a=   2

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What is an equation in point-slope form of the line that passes through the point (4, −1) and has slope 6?
AveGali [126]

Answer: A

Step-by-step explanation:

See attached picture

7 0
3 years ago
Please, can someone help?
LekaFEV [45]
The area of that figure is 2453.25 square feet

First, you would need to find the area of the rectangle

(L)(W)
(70)(30)
2100

Then since it is only a semi circle, the formula is pi*r^2/2

You find the area of a full circle first

(3.14)(15^2)
(3.14)(225)
706.5

Then you divide that by 2 since it’s only half a circle

706.5/2 = 353.25

Finally you add that by the area of the rectangle

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3 0
3 years ago
(2a^-2)(3a^3b^2)(c^-2)
aalyn [17]

Answer:

Step-by-step explanation:

7 0
2 years ago
Help needed asap !!!!!!
Zinaida [17]

Answer:

b)0, yes

Step-by-step explanation:

Given:

Vectors (4,8) . (6,-3)

Finding inner product of vectors:

= 4x6 + 8x-3

=24-24

=0

Now to check the angle between them using formula a.b=|a|.|b|cosθ

|a|= \sqrt{4^{2} +8^{2} } \\\sqrt{16+64}

   =8.9

|b|=\sqrt{6^{2} +(-3)^{2} } \\\sqrt{36+9}

   =6.7

Putting values of a.b=0 and |a|=8.9, |b|=6.7 in a.b=|a|.|b|cosθ we get,

0= 8.9(6.7)cosθ

cosθ =0

θ=90 degrees

Hence the two vectors are perpendicular !

7 0
3 years ago
Please help me in really confused
Marina86 [1]
The chart on the side should help you out. The width of a doorway is approximately 1 meter and the height of a skyscraper is 1,000 meters. Divide the height of the skyscraper by the width of the doorway to get your answer. It would take 1,000 door widths to make up the height of a skyscraper, so the height of the skyscraper is 1,000 times the width of the doorway.
5 0
3 years ago
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