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3 years ago

Lucy has played in six soccer matcher

Mathematics

2 answers:

garik1379 [7]3 years ago

6 0

Answer:

uhhhhhh ooooooookkkkkkk

Step-by-step explanation:

Elodia [21]3 years ago

6 0

Answer:

Lucy has played in six soccer matcher....

Step-by-step explanation:

You have to put the question

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WILL GIVE EXTRA BRAINLST HAVE A NICE DAy

Juli2301 [7.4K]

Answer: 1.) Irrational (because its not terminal)

2.) $2^{2}$

8 0

3 years ago

Solve for x . 8x-3 & 4x+3 8x-3+4x+3=180 ?x+_=180

STALIN [3.7K]

Answer:

x = 15

Step-by-step explanation:

the 2 angles are a linear pair and sum to 180° that is

8x - 3 + 4x + 3 = 180

12x = 180 ( divide both sides by 12 )

x = 15

6 0

2 years ago

Read 2 more answers

What is the degree of x^5-4x+2

8090 [49]

Answer:

degree 5

Step-by-step explanation:

the degree of a polynomial is determined by the term with the largest exponent and is the value of the exponent.

$x^{5}$ is the term with the largest exponent of 5

degree of polynomial is 5

8 0

4 years ago

The area of a swimming pool is 120 sq meters. The width of the pool is 8 meters. what is the length of the pool in centimeters ?

Genrish500 [490]

120/8 = 15m
15m = 150cm
Answer 150cm

3 0

3 years ago

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

Step-by-step explanation:

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

6 0

4 years ago