As we could "drag" these together, we could then do it the easy way.
56
+56
+56
-------
168
------------------------
Or we could also do the following:
56

3:
6

3= 18.
Carry the one.
5

3 = 15+1 (which was carried). = 16
(16+8) =
168
The answers are E.) y-int is (0,4), F.) domain of F(x) is all rel numbers , and C.) it is increasing
From the given ordered pair representing Jacinda's progress, her speed is equal to 10 miles per hour. Letting x be the time it takes for Jacinda to catch up with Raj, the total distance Raj would travel is
1.5 + 4.5x
and Jacinda's total distance is 10x. Mathematically,
1.5 + 4.5x = 10x
The value of x from the equation is 0.27 hours. Therefore, Jacinda needs to run 2.7 miles to catch up with Raj.