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2 years ago

14

Find h, assuming the triangles formed are similar.

2 answers:

Eddi Din [679]2 years ago

6 0

Answer:

h=18

Step-by-step explanation:

Alex2 years ago

6 0

Answer:

Step-by-step explanation:

Similar triangles, the sides are in proportion

$\frac{20}{8}=\frac{h}{6}\\\\\frac{20}{8}*6=h\\\\5*3=h\\$

h = 15

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Convert 10 meters to feet (round to the nearest tenth)

Alik [6]

Answer:

32.8 feet

Step-by-step explanation:

1 meter = 3.28084 feet

10 x 3.28084 = 32.8084

which rounds to <u><em>32.8</em></u>

5 0

3 years ago

Does crime pay? The FBI Standard Survey of Crimes showed that for about 80% of all property crimes (burglary, larceny, car theft

dedylja [7]

Answer:

The appropriate answer is "11 crimes".

Step-by-step explanation:

Let,

The number of crimes be "n".

Now,

⇒ $P(solved \ at \ least \ one) = 1-P(solved \ none \ of \ n)$

or,

⇒ $1-(0.8)^n>0.9$

⇒ $(0.8)^n$

By taking log both sides, we get

⇒ $n>=\frac{log(0.1)}{log(0.8)}$

By putting the values, we get

⇒ $n>=10.31$

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6 0

2 years ago

Mr. Kevin pays $37.95 per month for his cell phone with unlimited minutes. At this rate, what will his cellphone

masya89 [10]

$37.95 x12= 455.4 so Kevin’s cellphone will cost 455.4 for the year

5 0

3 years ago

Read 2 more answers

3xsquare-9x-30=0<br> What’s the answer

BartSMP [9]

Answer:

x = - 2 or x = 5

Step-by-step explanation:

Given

3x² - 9x - 30 = 0 ← in standard form

Divide all terms by 3

x² - 3x - 10 = 0

To factor the quadratic

Consider the factors of the constant term (- 10) which sum to give the coefficient of the x- term (- 3)

The factors are - 5 and + 2, since

- 5 × 2 = - 10 and - 5 + 2 = - 3, thus

x² - 3x - 10 = 0

(x - 5)(x + 2) = 0

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 2 = 0 ⇒ x = - 2

6 0

3 years ago

A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.

Verdich [7]

Answer:

$2a - 3b + 4c = 1$

Step-by-step explanation:

Given

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Required

Determine $2a - 3b + 4c$

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Open bracket

$a^2 + b^2 + c^2 = 2a - 2b - 2c - 3$

Equate the equation to 0

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0$

Express 3 as 1 + 1 + 1

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0$

Collect like terms

$a^2 - 2a + 1 + b^2 + 2b + 1 + c^2 + 2c + 1 = 0$

Group each terms

$(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

Factorize (starting with the first bracket)

$(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + b+b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + c+c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c(c + 1)+1(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)^2) = 0$

Express 0 as 0 + 0 + 0

$(a - 1)^2 + (b + 1)^2 + (c + 1)^2 = 0 + 0+ 0$

By comparison

$(a - 1)^2 = 0$

$(b + 1)^2 = 0$

$(c + 1)^2 = 0$

Solving for $(a - 1)^2 = 0$

Take square root of both sides

$a - 1 = 0$

Add 1 to both sides

$a - 1 + 1 = 0 + 1$

$a = 1$

Solving for $(b + 1)^2 = 0$

Take square root of both sides

$b + 1 = 0$

Subtract 1 from both sides

$b + 1 - 1 = 0 - 1$

$b = -1$

Solving for $(c + 1)^2 = 0$

Take square root of both sides

$c + 1 = 0$

Subtract 1 from both sides

$c + 1 - 1 = 0 - 1$

$c = -1$

Substitute the values of a, b and c in $2a - 3b + 4c$

$2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)$

$2a - 3b + 4c = 2 +3 -4$

$2a - 3b + 4c = 1$

7 0

3 years ago