Hope this helps you, and good luck in the future :)
Answer:
C) If the area of a square is an odd perfect square, the perimeter of the square will be even.
Step-by-step explanation:
Just did it on edge.
Answer:The given function is .Minimum or maximum value:At the extremum (maximum or minimum) value, the function will have zero slope. So, differentiate the given function once and equate it to zero to get the extremum point.dy/dx=0Now, check whether the point x=0 is corresponding to the maximum value or minimum value by differentiating the function twice,As for all value of x, so x=0 is the point corresponding to minima.Put x=0 in the given function to get the minimum value.Domain and range:The function defined for all the values of the independent variable, x.So, the domain is .The range of the function is the possible value of y.The minimum value, for x=0, is y=7.The maximum value, as .Hence the range of the function is .The value of x for which the function is increasing and decreasing:If the slope of the function is negative than the function is decreasing, soThen, from equation (i), the value of x for which dy/dx<0,18x<0Hence, the function is decreasing for .While if the slope of the function is positive than the function is increasing, soThen, from equation (i), the value of x for which dy/dx<0,18x>0Hence, the function is increasing for
Step-by-step explanation:hope this helps
When you solve, a quadratic formula is set up as ax^2+bx+c so in this scenario a is 1, b is -1 and c is -6.
-(-1)+- √- 1^2-4(1)(-1)/2(1) is
1+/-√1+4/2 equals -2 and 3 making the answer c
