Answer:
x = ![\frac{\sqrt[3]{468}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B468%7D%7D%7B6%7D)
or x =~ -1.29399
Step-by-step explanation:
Calculate the product. x^2 * 6x = 6x^3
divide both sides by 6. x^3 = -13/6
Take the root of both sides. x = ![\frac{\sqrt[3]{468}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B468%7D%7D%7B6%7D)
#21 is 95 degrees
#22 is B
Answer:
4
Step-by-step explanation:
lim (x^2 - 4) / (x - 2)
x --> 2
When we plug x =2, we get
(2^2 - 4) / (2 - 2)
= (4 - 4)/(2 - 2)
= 0 /0
Which is undefined.
Now we have to use L'hospital rule. Which says we need to differentiate the numerator and the denominator and apply the limit.
When we differentiate x^2 -4, we get 2x
When we differentiate x -2, we get 1
lim 2x/1
x --> 2
Now apply, the limit x = 2
2(2)/1
= 4/1
= 4
Therefore, limit of this function is 4, when x tends to 2.
Hope you will understand the concept.
Thank you.
Answer:
16.24 Units
Step-by-step explanation:
The perimeter of the triangle is the sum of the length of the sides of the triangle. Given the points on the vertices, the length of each side may be found using the formula
Length = √(x2 - x1)^2 + (y2 - y1)^2
Considering the pair (-1, 2), (3, 1), the length of that side
= √(3 -- 1)^2 + (1-2)^2)
= √(16 + 1)
= √17 units
Considering the pair (-1, 2), (7, 2), the length of that side
= √(7 -- 1)^2 + (2-2)^2)
= √(64)
= 8
Considering the pair (3, 1), and (7, 2), the length of that side
= √(7 - 3)^2 + (2 - 1)^2
= √(16 + 1)
= √17
Hence the perimeter of the triangle
= √17 + 8 + √17
= 4.12 + 8 + 4.12
= 16.24 Units