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Flura [38]
3 years ago
6

A survey of 125 households was done to investigate whether households have laptops, tablets, or

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0

Answer:

3) 0.326

Step-by-step explanation:

Total Number of surveyed households =125

We want to determine the probability that a randomly selected household would have a laptop given that it does not  have a tablet.

Written in Probability notation: P(Laptop|No Tablet)

P(Laptop|No Tablet)=\dfrac{P(L\cap T')}{P(T')} \\=\dfrac{31/125}{95/125}\\=\dfrac{31}{95}\\\\=0.326

The correct option is C,

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Answer and Step-by-step explanation: P(X) calculated by the binomial probability formula is:

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P(20) = \left[\begin{array}{ccc}53\\20\end{array}\right] .(0.3)^{20}.(1-0.3)^{33}

P(20) = \frac{53!}{33!.20!}.3.5.10^{-11}.7.7.10^{-6}

P(20) = 0.0552

To determine whether the normal distribution can be used to estimate this probability, both n.p and n.(1-p) must be greater than 5:

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z-score = 0.8907

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Step-by-step explanation:

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