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maw [93]
3 years ago
8

Give two examples (i.e. list 2 elements that are examples) of: a. an atom with a half-filled subshell b. an atom with a complete

ly filled outer shell c. an atom with its outer electrons occupying a half-filled subshell and a filled subshell
Chemistry
1 answer:
algol [13]3 years ago
4 0

Answer:

an atom with a half-filled subshell - hydrogen

an atom with a completely filled outer shell - argon

an atom with its outer electrons occupying a half-filled subshell and a filled subshell- copper

Explanation:

The outermost shell or the valence shell of the atom is the last shell in the atom. Chemical reactions occur at this outer most shell. The number of electrons on the outermost shell of an atom determines the group to which it belongs in the periodic table as well as its chemical properties.

Hydrogen has a half filled 1s sublevel. Only one electron is present in this sublevel.

Let us consider argon

1s2 2s2 2p6 3s2 3p6

The outermost ns and np levels are completely filled. Thus the outermost shell is completely filled.

In the last case; let us look at the electronic configuration of nitrogen;

1s2 2s2 2p3

The outermost 2p subshell is exactly half filled while the 2s sublevel is fully filled. The outermost shell of nitrogen is made up of 2s2 and 2p3 sublevels.

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Ann [662]

Answer: I am unsure of what you mean.

Explanation:

Please explain better.

6 0
4 years ago
2Al+ Fe203 Al203 +2Fe
leonid [27]

Answer:

229 g Al₂O₃; 243 g Fe₂O₃

Explanation:

We have the masses of two reactants, so this is a <em>limiting reactant problem</em>.  

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

Step 1. <em>Gather all the information</em> in one place with molar masses above the formulas and masses below them.  

M_r:      26.98    159.69    101.96

              2Al   +   Fe₂O₃ ⟶ Al₂O₃ + 2Fe

Mass/g:  121          601

===============

Step 2. Calculate the <em>moles of each reactant </em>

Moles of Al         = 121 × 1/26.98

Moles of Al         = 4.485 mol Al

Moles of Fe₂O₃  = 601× 1/159.69

Moles of Fe₂O₃  = 3.764 mol Fe₂O₃

===============

Step 3. Identify the <em>limiting reactant</em>  

Calculate the moles of Al₂O₃ we can obtain from each reactant.  

<em>From Al </em>

The molar ratio is 1 mol Al₂O₃:2 mol Al

Moles of Al₂O₃ = 4.485 × 1/2

Moles of Al₂O₃ = 2.242 mol Al₂O₃

<em>From Fe₂O₃</em>:

The molar ratio is 1 mol Al₂O₃:1 mol Fe₂O₃

Moles of Al₂O₃ = 3.764 × 1/1

Moles of Al₂O₃ = 3.764 mol Al₂O₃

The <em>limiting reactant</em> is Al because it gives the smaller amount of Al₂O₃.

The <em>excess reactant</em> is Fe₂O₃.

===============

Step 4. Calculate the <em>mass of Al₂O₃ formed </em>

Mass of Al₂O₃ = 2.242 × 101.96

Mass of Al₂O₃ = 229 g Al₂O₃

===============

Step 5. Calculate the <em>moles of Fe₂O₃ reacted </em>

The molar ratio is 1 mol Fe₂O₃:2 mol Al:

Moles of Fe₂O₃ = 4.485 × ½

Moles of Fe₂O₃ = 2.242 mol Fe₂O₃

===============

Step 6. Calculate the <em>moles of Fe₂O₃ remaining </em>

Moles remaining = original moles – moles used

Moles remaining = 3.764 – 2.242

Moles remaining = 1.521 mol Fe₂O₃

==============

Step 7. Calculate the <em>mass of Fe₂O₃ remaining </em>

Mass of Fe₂O₃ = 1.521 × 159.69/1

Mass of Fe₂O₃ = 243 g Fe₂O₃

3 0
4 years ago
What is the definition of a physical property of matter?
Bezzdna [24]
<span>Physical properties are any properties of matter which can be perceived or observed without changing the chemical identity of the sample.</span>
7 0
3 years ago
The mass of an electron is
stealth61 [152]
The mass of an electron is:
 0.00054386734 or 9.1 x <span>10^-31 kg</span><span>.
</span>Good Luck!!
4 0
3 years ago
Read 2 more answers
Object A has a mass of 12g and a volume of 8cm3. object B has a mass of 20g and a volume of 8cm3 . which object has a greater de
Charra [1.4K]

Answer:

Object B has a density of 2.5 g/cm³ which is greater than object A by 1 g/cm³

Explanation:

Since we know that the formula for density is d=m/v, we can divide each mass by its corresponding volume to find the densities

12/8=1.5

20/8=2.5

So we know that object B has a greater density than object A by 1 g/cm³ (gram per cubic centimeter). Also the standard unit for density is kilograms per cubic meter but I used gram per cubic centimeter since they were the given units. 1cm=100m, 1000g=1km

3 0
4 years ago
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