Which of the following is an example of representative money?

How many grams of CO2 are produced from 6.7 L of O2 gas at STP?

Tasya [4]

<h3>Answer:</h3>

13 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Moles
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

Using Dimensional Analysis

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] 6.7 L O₂

[Solve] g O₂

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

[PT] Molar Mass of O: 16.00 g/mol

[PT] Molar Mass of C: 12.01 g/mol

Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 6.7 \ L \ O_2(\frac{1 \ mol \ O_2}{22.4 \ L \ O_2})(\frac{44.01 \ g \ O_2}{1 \ mol \ O_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 13.1637 \ g \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

13.1637 g CO₂ ≈ 13 g CO₂

5 0

3 years ago

2A(g) + B(l) ⇌ 3C(aq) + D(s)

makvit [3.9K]

Answer:

B

[(0.75)^3(0.25)]÷[(0.50)^2(0.75)]

Explanation:

toppr dot com

8 0

3 years ago

Assume that the variables x and y are directly related. If k = 8, what is the value for each of the following polnts? Be sure

Ede4ka [16]

Calculus, originally called infinitesimal calculus or "the calculus of infinitesimals", is the mathematical study of continuous change, in the same way that geometry is the study of shape and algebra is the study of generalizations of arithmetic operations.

3 0

3 years ago

If 27 ml of 6.0 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?

katrin [286]

The minimum mass of NaHCO3 that must be added to the spill to neutralize the acid is 27.216 grams

<h3>calculation </h3>

write the balanced chemical equation

2NaHCO3 +H2SO4 → Na2SO4 +2H2O +2CO2

find the moles of H2SO4 = molarity x volume in liters

volume in liters = 27/1000=0.027 l

moles is therefore= 0.027 x6=0.162 moles

by use of mole ratio of NaHCO3: H2SO4 which is 2:1 the moles of NaHCO3=0.162 x2=0.324 moles

mass of NaHCO3= moles of NaHCO3 x molar mass of NaHCO3(84g/mol)

= 84g/mol x 0.324=27.216 grams

8 0

4 years ago

Read 2 more answers

12.1 g CoCl3 calculate the amount, in moles

elena-s [515]

Answer:

Number of moles of CoCl3 = 0.09 moles

Explanation:

Given data:

Mass of CoCl₃ = 12.1 g

Number of moles = ?

Solution:

First of all we will calculate the molar mass.

Molar mass of CoCl3 = 28.01 + (35.5×3)

Molar mass of CoCl3 = 28.01 + 106.5

Molar mass of CoCl3 = 134.51 g/mol

Number of moles of CoCl3 = mass / molar mass

Number of moles of CoCl3 = 12.1 g/134.51 g/mol

Number of moles of CoCl3 = 0.09 moles

4 0

4 years ago