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Lelu [443]
3 years ago
7

A gas is compressed from an initial volume of 5.35 L to a final volume of 1.23 L by an external pressure of 1.00 atm. During the

compression the gas releases 128 J of heat.
Required:
What is the change in internal energy of the gas?
Chemistry
1 answer:
kotykmax [81]3 years ago
8 0

Answer:

The change in internal energy is  \Delta  U  =  417331 \ J

Explanation:

From the question we are told that

    The initial volume is  V_i =  5.35 \ L

        The final volume is  V_f  =  1.23 \ L

     The value of the external pressure is  P  = 1.00 \ atm =  1 * 101325 =  101325 \Pa

      The energy released by the gas is  Q=  -128 \ J

The negative sign show that energy is released from the system

       

Generally  the workdone on the gas is mathematically represented as

         W =   P (V_i - V_f)

substituting values

         W =  101325 *(1.23 - 5.35)

        W =  - 4.17*10^{5} \ J

The change in internal energy is mathematically evaluated as

         \Delta  U  =  Q -  W

substituting values

         \Delta  U  =  -128  -  (-4.17*10^{5})

        \Delta  U  =  417331 \ J

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a) \Delta S

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The energy balance:

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If the process is isothermical the U doesn't change:

0=[tex]\delta Q- \delta W

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The work:

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If it is an ideal gas:

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