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IgorLugansk [536]

4 years ago

8

Solve for x.. please help

2 answers:

Genrish500 [490]4 years ago

4 0

The answer for this problem is that x = 60°, or B.

We can solve this problem by using our knowledge of quadrilaterals. In this problem, we need to know that the number of degrees in a quadrilateral is equal to 360, but, the formula to find the number of degrees in a polygon with n sides is (n-2) * 180.

Now that we know that the sum of the angles if 360°, we can add all the angles and solve for x. The angles with the squares are 90°.

2x° + x° + 90° + 90° = 360°

Get x by itself, combine like terms.

3x° + 180° - 180° = 360° - 180°
3x° = 180°
x = 60°, or B.

Crazy boy [7]4 years ago

3 0

∠Q and ∠S are both 90°. This means they add up to 180°, and ∠R and ∠P both add up to 180° as well (because this is a quadrilateral and all interior angles add up to 360°).

2x + x = 180
Combine like terms.

3x = 180
Divide both sides by 3.

x = 60
B) 60

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7 0

3 years ago

Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr

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C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Distance between B(0, 5) and C(4, 2):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(0, 5) = (x_1, y_1)$

$C(4, 2) = (x_2, y_2)$

$BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}$

$BC = \sqrt{(4)^2 + (-3)^2}$

$BC = \sqrt{16 + 9} = \sqrt{25}$

$BC = 5 units$

Distance between C(4, 2) and D(1, -2)

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(4, 2) = (x_1, y_1)$

$D(1, -2) = (x_2, y_2)$

$CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}$

$CD = \sqrt{(-3)^2 + (-4)^2}$

$CD = \sqrt{9 + 16} = \sqrt{25}$

$CD = 5 units$

Distance between E(-2, -2) and F(-5, 2):

$EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$E(-2, -2) = (x_1, y_1)$

$F(-5, 2) = (x_2, y_2)$

$EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}$

$EF = \sqrt{(-3)^2 + (4)^2}$

$EF = \sqrt{9 + 16} = \sqrt{25}$

$EF = 5 units$

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0

3 years ago