Answer:
125feet
Step-by-step explanation:
Given the equation that modeled the height expressed as h = -16t^2 + 80t + 25, where h is the height and t is the time in seconds.
The arrow reaches the maximum height at dh/dt = 0
dh/dt = -32t + 80
0= -32t+80
32t = 80
t = 80/32
t = 2.5secs
substitute t = 2.5 into the formula;
h = -16t^2 + 80t + 25
h = -16(2.5)^2 + 80(2.5) + 25
h = -16(6.25)+225
h = -100+225
h = 125
Hence the maximum height the arrow reaches is 125feet
At around 20'000ft. and higher.
Answer:
Step-by-step explanation:
A to C
y = b + mx
b = y-intercept
m = slope of line
Looking at the line, the line crosses the y-axis at the coordinates (0,0). This means that the y-intercept is 0.
The slope formula is m=(y2-y1)/(x2-x1). Using the points on the line (-1, -3) and (1,3) we find that the slope is, 3.
Looking back we can see that our variables now have value so we can plug them into our formula.
y = b + mx
b = 0
m = 3
Substitute
y = 0 + 3x
You divide -15 on both sides to keep the x alone
-240/ -15=16
A negative divided by a negative is a positive so x=16
The large scoop holds 48 units.
36/0.75 = 48
