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lapo4ka [179]
3 years ago
6

Plzzz help need it right nowww.....

Mathematics
1 answer:
Hunter-Best [27]3 years ago
5 0
2x-5= - 20 


2x=-20+5
 
          Add  \ 5 \ to \ both \ sides
 

2x=-15

 
 

x=- \dfrac{15}{2}       Divide \ both \ sides \ by \ 2
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After the booster club sold 40 hotdogs at a football game, it had 90$ in profit. After the next game, it had sold a total of 80
sergiy2304 [10]
Let's first establish what we already know for this problem.

x = total number of hotdogs sold
y = total profit from total sales of hotdogs

Let's also establish the other equations which we will require in order to solve this problem.

Equation No. 1 -
Profit for 40 hotdogs = $90 profit

Equation No. 2 -
Profit for 80 hotdogs = $210 profit

STEP-BY-STEP SOLUTION

From this, we can use the formula y = mx + b & substitute the values for x & y from one of the two previous equations into the formula in order to obtain the values of m & b for the final equation. Here is an example of the working out as displayed below:

Firstly, using the first or second equation, we make either m or b the subject. Here I have used the first equation and made m the subject:

Equation No. 1 -
y = mx + b
90 = m ( 40 ) + b
40m = 90 - b
m = ( 90 - b ) / 40

Now, make b the subject in the second equation as displayed below:

Equation No. 2 -
y = mx + b
210 = m ( 80 ) + b
210 = 80m + b
b = 210 - 80m

Then, substitute m from the first equation into the second equation.

Equation No. 2 -
b = 210 - 80m
b = 210 - 80 [ ( 90 - b ) / 40 ]
b = 210 - [ 80 ( 90 - b ) / 40 ]
b = 210 - 2 ( 90 - b )
b = 210 - 180 - 2b
b - 2b = 30
- b = 30
b = - 30

Now, substitute b from the second equation into the first equation.

Equation No. 1 -
m = ( 90 - b ) / 40
m = ( 90 - ( - 30 ) / 40
m = ( 90 + 30 ) / 40
m = 120 / 40
m = 3

Through this, we have established that:

m = 3
b = - 30

Therefore, the final equation to model the final profit, y, based on the number of hotdogs sold, x, is as follows:

y = mx + b
y = ( 3 )x + ( - 30 )

ANSWER:
y = 3x - 30
3 0
3 years ago
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