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mixer [17]
4 years ago
9

If the size of a scale drawing is 50 x 36 cm and the scale factor is 5:1 what is the size of the actual object?

Mathematics
1 answer:
inna [77]4 years ago
5 0

Answer:

50*30=1500

Step-by-step explanation:

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Find the slope with points -5,0and 5,-8
amm1812

Answer:

-.8 or -4/5

Step-by-step explanation:

8 0
3 years ago
The mayor is interested in finding a 95% confidence interval for the mean number of pounds of trash per person per week that is
Hatshy [7]

Answer:

A. <u>Normal</u>

B. <u>30.1</u>, <u>32.9</u>

C. <u>95</u>, <u>5</u>

Step-by-step explanation:

A. The sampling distribution follows a <u>normal</u> distribution

Given that the sample size is large, we have that the sample distribution follows a normal distribution according to the central limit theorem

B. The 95% confidence interval is given as follows;

CI=\bar{x}\pm z \times \dfrac{s}{\sqrt{n}}

The number of residents in the study, n = 120 residents

The sample mean, \overline x = 31.5 pounds

The standard deviation, s = 7.8 pounds

The z-value for 95% confidence level, z = 1.96

Therefore, we get;

C.I. = 31.5 ± 1.96 × 7.8/√(120)

The 95% C.I. ≈ 30.1 ≤ \overline x ≤ 32.9

Therefore, we have that with 95% confidence, the population mean number of pounds per person per week is between <u>30.1</u> and <u>32.9</u>

C. Therefore, according to the central limit theorem, about <u>95</u> percent of the groups of 120 will contain the true population mean number of pounds of trash generated per person per week and about <u>5</u> percent will not contain the true population mean number of pounds of trash generated per person per week.

8 0
3 years ago
Complete this sentence. If the mass of an object ________, the weight of an object will _______________.
CaHeK987 [17]
Simple. Mass has to do with weight, so if mass decreases then so will the weight
6 0
3 years ago
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Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
I’ll give points + brainslist, if you don’t know don’t bother answering (:
yarga [219]

Answer:

I think that its D

Step-by-step explanation:

..

5 0
3 years ago
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