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Mashcka [7]
3 years ago
5

In a box there are 50 counters :white ones,blue ones and red ones .There are eleven times as many white ones as blue ones.There

are less red ones than white ones, but more read ones than blue ones .By how much is the number of red counters less than the number of white counters ?
Mathematics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

  • 33 white, 3 blue, 14 red

Step-by-step explanation:

  • White = w, Blue = b, Red = r

<u>Given:</u>

  • w = 11b
  • r < w
  • b < r
  • w + b + r = 50

<u>The last equation can be written as:</u>

  • 11b + b + r = 50
  • 12b + r = 50

<u>Possible values of b are 1, 2, 3, 4</u>

  • Since b < r, we exclude b = 4

<u>If b = 1</u>

  • w = 11,
  • r = 50 - 12 = 38 but number of red should be less than white, excluded as r < w is not met

<u>If b = 2</u>

  • w = 22,
  • r = 50 - 24 = 26, still same condition as above, excluded as r < w is not met

<u>If b = 3</u>

  • w = 33,
  • r = 50 - 36 = 14, this is the only correct option to consider
lions [1.4K]3 years ago
4 0

Answer:

Find the question mark using the model I've provided and that'll be the answer!

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