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xenn [34]
3 years ago
6

I’m stuck can someone help me thank you

Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer:

the answer may be 127.

Step-by-step explanation:when you add 90° + 37° you will get the answer 127

I am not sure.

You might be interested in
If LM = MK, LK =7x-10, KN = x+3, MN = 9x-11, and KJ =28, find LJ
marusya05 [52]

Answer:


Step-by-step explanation:

Suppose J, K, L, M, N are points on the same line.


MK = MN + (-KN) = MN - KN = 9x - 11 - x - 3 = 8x - 14


Since LK = MK and LK = 7x - 10, then


7x - 10 = 8x - 14


8x - 7x = -10 + 14


x = 4


LJ = MK + KJ


MK = LK = 7x - 10 = 7(4) - 10 = 28 - 10 = 18


LJ = 18 + 28 = 46


Read more on Brainly.com - brainly.com/question/5067118#readmore

8 0
3 years ago
Read 2 more answers
Help please !!!!!!!! ASAP
fgiga [73]

Answer:

C

Step-by-step explanation:

3 1/2 x 2 = 7

5 0
2 years ago
I need help. Thank you.
soldier1979 [14.2K]

Answer:

27

Step-by-step explanation:

green is 30%

blue is 50%

red is 6 marbles which when calculated is equal to 20%

blue would then be 15 marbles as the whole 100% would equal to 30 marbles

if 40% is added which is also 12 marbles then 15+12 = 27

7 0
2 years ago
Math question please show work don't guess
iVinArrow [24]

Let x = the unknown angle

sine of an angle is measure of the opposite leg divided by the hypotenuse.

sin x = 10/21

To now solve for x, we so the inverse of sine.

sin⁻¹(10/21) = x

Plug this into your calculator.

x ≈ 28.44 degrees. This would round down to 28 degrees, option B is your answer.

5 0
3 years ago
Read 2 more answers
An equality that represents numbers that are not a solution of x-1.2>2.8
ValentinkaMS [17]

The solution is x> 4 or x ∈(4,∞)

Here equality given is

x - 1.2> 2.8

Rearrange the variable to the left side of the equation

x > 2.8 + 1.2

Calculate the sum

x > 4

Or we can also say

x ∈ (4,∞)

Therefore the range of x is x∈ (4,∞).

To know more about the range of the solution refer to the link given below:

brainly.com/question/2264373

#SPJ1

4 0
7 months ago
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