Answer:
234 times
Step-by-step explanation:
<u>Number of times the number 7 appears in a hundred</u>
7 as units digit (07-17-27 ..... 97): 10 times
7 as tens digit (70-71-72..... 79): 10 times
20 times the digit 7 appears in first one hundred (0-100)
Let's calculate how many times 7 would be as units or tens in 7 hundreds
20X7 = 140 times digit 7 appears until number 699
<u>Now, from 700 to 777</u>
7 as hundreds digit (700-701-702 .... 777): 78 times
7 as tens digit (770-771-772 .... 777): 8 times
7 as units digit (707-717-727....777): 8 times
78 + 8 + 8 = 94 times the digit 7 appears in the range 700 - 777. Plus 140 times
140 + 94 = 234 times
Answer: A. As x → ∞, f(x) → ∞, and as x → –∞, f(x) → ∞.
Answer:
Step-by-step explanation:
The problem relates to filling 8 vacant positions by either 0 or 1
each position can be filled by 2 ways so no of permutation
= 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
= 256
b )
Probability of opening of lock in first arbitrary attempt
= 1 / 256
c ) If first fails , there are remaining 255 permutations , so
probability of opening the lock in second arbitrary attempt
= 1 / 255 .