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Dominik [7]
2 years ago
10

What is 62.5% as a decimal

Mathematics
2 answers:
zepelin [54]2 years ago
4 0

Answer:

0.625

Step-by-step explanation:

please give me brainliest :(

Mrrafil [7]2 years ago
3 0

Answer:

0.625

Step-by-step explanation:

How to Convert a Percent to a Decimal

Here are two ways to convert a percent to a decimal,

1. Divide a percent by 100 and remove the percent sign to convert from a percent to a decimal.

Example: 62.5% becomes 62.5/100 = 0.625

2. This way is easier and faster. Start by removing the percent sign and moving the decimal point 2 places to the left.

Example: 62.5%

⇒ 62.5

⇒ 6.25

⇒ .625

Hence, the answer is 0.625.

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Combine like radicals to get your answer. <br><br> image attached
spin [16.1K]

Answer:

So the final answer is

-8\sqrt{3}

Step-by-step explanation:

Radicals:

In mathematics, a radical expression is defined as any expression containing a radical (√) symbol. Many people mistakenly call this a 'square root' symbol, and many times it is used to determine the square root of a number. However, it can also be used to describe a cube root, a fourth root, or higher.

The given expression is

-5\sqrt{3} -3\sqrt{3}

Now take common radical out so we will get

\sqrt{3}(-5-3)

Now add the Parenthesis part.

\sqrt{3}(-8)

So the final answer is

-8\sqrt{3}

5 0
3 years ago
Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.
borishaifa [10]

We have the equation

20y=x^2-10-15

Let's complete the square, to do it let's add and subtract 25 on the right side

\begin{gathered} 20y=x^2-10-15+25-25 \\  \\ 20y=(x-5)^2-15-25_{} \\  \\ 20y=(x-5)^2-40 \\  \\  \end{gathered}

Now we can have y in function of x

\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\  \\  \end{gathered}

Now we can already identify the vertex because it's in the vertex form:

y=a(x-h)+k

Where the vertex is

(h,k)

As we can see, h = 5 and k = -2, then the vertex is

(5,-2)

Now we can continue and find the focus, the focus is

\mleft(h,k+\frac{1}{4a}\mright)

We have a = 1/20, therefore

\begin{gathered} \mleft(5,-2+5\mright) \\  \\ (5,3) \end{gathered}

The focus is

(5,3)

And the last one, the directrix, it's

y=k-\frac{1}{4a}

Then

\begin{gathered} y=-2-5 \\  \\ y=-7 \end{gathered}

Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

5 0
1 year ago
F(x) = cot x PRE CALC HELP PLS?!
alisha [4.7K]
Check the picture below.

is it even?  well, even functions use the y-axis as a mirror, so a pre-image on the right-side, will be a mirror of the image on the left-side, but in this case it isn't so, if you put a mirror right on the y-axis, the left-side will look a bit different.

does it have a zero at x = 0?  well, just look at the graph, is the line touching the x-axis at 0? nope.

does it have an asymptote at 0?  well, surely you can see it right there.

8 0
3 years ago
Please help?
Mazyrski [523]

Answer:

23\sqrt{3}\ un^2

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\

2. Note that

A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

7 0
3 years ago
The ratio of the length of an airplane wing to its width is 9 to 1. If the length of a wing is 34.7 meters, how wide must it be?
KIM [24]
The answer is  3.85555556 because the ratio is 9:1 the length 34.7  so that means the length will be 9 times the width so you divide.

6 0
3 years ago
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