If your solving for x, x=2
Answer:

Step-by-step explanation:
We can write a rational function.
We need to make sure our denominator both have zeroes at 3 and 10.
Set an equation equal to zero to find the function




So we would represent that's as

and

Multiply the two binomial together.

Let our numbetator be any interger.
Use any equation as long as the quadratic is the denominator and the interger is the numerator.

Answer:
x = 10
Step-by-step explanation:
2x/3 + 1 = 7x/15 + 3
<em><u>(times everything in the equation by 3 to get rid of the first fraction)</u></em>
2x + 3 = 21x/15 + 9
<em><u>(times everything in the equation by 15 to get rid of the second fraction)</u></em>
30x+ 45 = 21x + 135
<em><u>(subtract 21x from 30x; subtract 45 from 135)</u></em>
9x = 90
<em><u>(divide 90 by 9)</u></em>
x = 10
<h2>
Another solution:</h2>
2x/3 + 1 = 7x/15 + 3
<u><em>(find the LCM of 3 and 15 = 15)</em></u>
<u><em>(multiply everything in the equation by 15, then simplify)</em></u>
10x + 15 = 7x + 45
<u><em>(subtract 7x from 10x; subtract 15 from 45)</em></u>
3x = 30
<em><u>(divide 30 by 3)</u></em>
x = 10
Answer:
x^2 + (y+1)^2 = 10^2
Step-by-step explanation:
Centre (p,q) = (0, -1)
radius, r = 10
General Equation of a circle
(x-p)^2 + (y-q)^2 = r^2
(x-0)^2 + (y- -1)^2 = 10^2
x^2 + (y+1)^2 = 10^2
Answer:
Step-by-step explanation:
a) 
Substitute limits to get
= 
Thus converges.
b) 10th partial sum =

=
c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)
where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .
(question is not clear)