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2 years ago

Please help with this

Mathematics

2 answers:

ratelena [41]2 years ago

6 0

Answer:

5x^2+10

Step-by-step explanation:

the formula for area is height x width.

the question tells us that this rectangle has a height of 5 and a width of x^2+2

so, if we substitute these values into our formula for area we get 5 (x^2+2)

multiply 5 by every term in the brackets to get your final answer, 5x^2+10

artcher [175]2 years ago

4 0

Answer:

5x^2+10

Step-by-step explanation:

(5)×(x^2+2) so....distribute

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It's in Danish but I will translate it for you. :)

Nuetrik [128]

<span>
B) Determine y when x = 10 and solve the equation y = 18 (where you print y with the right side in your specification)</span>

8 0

2 years ago

Interior angle of triangles

Neporo4naja [7]

I'm not sure what you are looking for. If you want to know the total number of degrees that interior angles of triangles total, they add up to 180°.

Hope this helps! :)

7 0

2 years ago

Lucy has 4 inches of ribbon that she wants to cut into 6 equal sized pieces. What is true about the length of each piece of ribb

PolarNik [594]

Answer:

Option C

Step-by-step explanation:

Given

Total length of ribbon lucy has=4 inches

She wants to divide it into 6 equal sized pieces so

Length of each piece=4/6

This can also be written as:

Length of each piece=4*(1/6 )

Now we will look at the options one by one:

For A, Each piece has 6/4 inches of ribbon.. This statement is not true as we have to divide 4 inches into 6 pieces so 4 is supposed to be in the numerator.

For B, breaking down 4/6 gives us 4*(1/6), so the statement is not true.

For C , as we can see that the expression is 4*(1/6), each piece will have 1/6 of inches of ribbon.

So option C is the correct answer..

6 0

2 years ago

There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit

Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a $\frac{3}{11}$ chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is $\frac{8}{11}$ , and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

$\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}$

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is $\frac{2}{11}$ , and the probability of picking the second red ball is $\frac{1}{10}$ and the probability of picking the green ball is $\frac{1}{9}$ . We want to multiply thm again, as per the multiplication rule like the last problem.