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Dennis_Churaev [7]
3 years ago
6

Two ways to write a algebraic expression of n-5

Mathematics
2 answers:
Advocard [28]3 years ago
6 0
<span>Two ways to write a algebraic expression of n-5:

n + (-5)
or
-5 + n
hope it helps</span>
deff fn [24]3 years ago
5 0
-5 + n is another way to write the expression. 
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The sum of a whole number and twice its square is 21. Find the whole number
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SOLUTION:

Let whole number = x

x + 2x^2 = 21

2x^2 + x - 21 = 0

2x^2 + 7x - 6x - 21 = 0

x ( 2x + 7 ) - 3 ( 2x + 7 ) = 0

( 2x + 7 ) ( x - 3 ) = 0


2x + 7 = 0

2x = - 7

x = - 7 / 2

OR

x - 3 = 0

x = 3


ANSWER:

Therefore, as 3 is a whole number while - 7 / 2 isn't a whole number, the whole number must be 3.

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3 years ago
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aleksandrvk [35]

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Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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3 years ago
Solve the given system by the substitution method. <br>3x + y = 14 <br>7x - 4y = 20​
Eva8 [605]

Answer:

(4, 2 )

Step-by-step explanation:

Given the 2 equations

3x + y = 14 → (1)

7x - 4y = 20 → (2)

Rearrange (1) making y the subject by subtracting 3x from both sides

y = 14 - 3x → (3)

Substitute y = 14 - 3x into (2)

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Substitute x = 4 into (3) for corresponding value of y

y = 14 - 3(4) = 14 - 12 = 2

solution is (4, 2 )

8 0
2 years ago
Read 2 more answers
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