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amm1812
3 years ago
7

Any youngboy fan out here ? He already dead..

Mathematics
2 answers:
victus00 [196]3 years ago
4 0

Answer:

wow

Step-by-step explanation:

eduard3 years ago
4 0

Answer:

i like nba youngboy

Step-by-step explanation:

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If the sales tax is 3.5%, what is the cost of a pair of shoes with a price of $120? show work
Fudgin [204]
If you multiply 120 to 3.5% but in decimal form which is 0.035 you’ll get 4.2 and then add the 4.2 and 120 together and you get your answer with is $124.20
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Ngl i forgot whats 23+41
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64 is the answer and apparently it needs to be longer than 20 characters
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defon
I believe the answer is A.
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Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The
Tems11 [23]

Answer:

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

They randomly survey 387 drivers and find that 298 claim to always buckle up.

This means that n = 387, \pi = \frac{298}{387} = 0.77

84% confidence level

So \alpha = 0.16, z is the value of Z that has a p-value of 1 - \frac{0.16}{2} = 0.92, so Z = 1.405.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

6 0
3 years ago
He is 15 years old this is 6 years younger than his sister Victoria write and solve a subtraction equation to find Victorious ag
Vedmedyk [2.9K]
15+6=21
Victoria's age=21
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