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V125BC [204]
3 years ago
11

1. A rectangular swimming pool measures 12 cm by 15 cm. What is the area of the pool?

Mathematics
1 answer:
igomit [66]3 years ago
8 0

1) 180 square cm

Answer:

2) 41 cubic cm

Step-by-step explanation:

1)

Area of pool = 12 * 15 = 180 square cm

2) Volume of water = 1/3 * Volume of pool

= 1/3 *123

= 41 cubic cm

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An inequality is a relation which makes a non equal comparison between two of more numbers or other mathematic equations. > I'd greater than < is less than = equal to. ≥ is greater than or equal ≤ less than or equal to. = equal to ≠ not equal

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E

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If Hal multiplies one side of the equation below by 7, what does he need to do to balance the equation? 56 + 124 = 180 A Add 7 t
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A veterinarian is enclosing a rectangular outdoor running area against his building for the dogs he cares for. He needs to maxim
NISA [10]

Answer:

a) The length of the building that should border the dog run to give the maximum area = 25feet

b)    The maximum area of the dog run  = 1250 s q feet²

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given function </em>

<em>                        A(x) = x (100-2x)</em>

<em>                       A (x) = 100x - 2x²...(i)</em>

<em>Differentiating equation (i) with respective to 'x'</em>

<em>              </em>\frac{dA}{dx} = 100 (1) - 2 (2x)<em></em>

<em>      ⇒    </em>\frac{dA}{dx} = 100 - 4 x      ...(ii)

<em>Equating  zero</em>

         ⇒ 100 - 4x =0

         ⇒  100 = 4x

Dividing '4' on both sides , we get

             x = 25

<em>Step(ii):</em>-

Again differentiating equation (ii) with respective to 'x' , we get

    \frac{d^{2} A}{dx^{2} } = -4 (1) < 0

Therefore The maximum value at x = 25

The length of the building that should border the dog run to give the maximum area = 25

<u>Step(iii)</u>

  Given  A (x) = x ( 100 -2 x)

substitute  'x' = 25 feet

             A(x) = 25 ( 100 - 2(25))

                    = 25(50)

                   = 1250

<u><em>Conclusion</em></u>:-

   The maximum area of the dog run  = 12 50  s q feet²

 

<em>    </em><em>                    </em>

<em></em>

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