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V125BC [204]
3 years ago
9

Click on all the values for n that make this inequality true

Mathematics
1 answer:
Ivenika [448]3 years ago
6 0
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Some rectangular tiles measure 15 cm by 9 cm . What is the length of the side of the smallest square area that can be covered by
vazorg [7]

Answer:

45 cm

Step-by-step explanation:

Find LCM(15,9). First factor both numbers:

15=3\cdot 5\\ \\9=3\cdot 3

So,

LCM(15,9)=3\cdot 5\cdot 3=45

This means that the length of the side of the smallest square area that can be covered by these tiles is 45 cm.

Practically, you can put 3 tiles in a row (to make 3 lenghts of 15 cm each that add up to 45 cm) and put such 5 rows (to make 5 lengths of 9 cm that add up to 45 cm).

6 0
3 years ago
What is the solution to this equation? log6(x) + log6(3) = log6( x+1)
stepladder [879]

Answer:

A

Step-by-step explanation:

got it right

7 0
4 years ago
Please help me with this im pretty confused ​
Vadim26 [7]

Answer:

3

Step-by-step explanation:

We are looking for the cube root of 27

x*x*x = 27

What number times itself 3 times is 27

3*3*3 =27

6 0
3 years ago
Read 2 more answers
Complete the square to solve the equation below check all that apply x^2+8x-5=15
Feliz [49]

Answer: x=-10\\x=2

Step-by-step explanation:

x^2+8x-5=15

Subtract 15 on both sides.

x^2+8x-5-15=15-15

x^2+8x-20=0

Solve ;

(x+10)(x-2)=0

x+10=0\\x=-10

x-2=0\\x=2

5 0
3 years ago
5. Draw lines to match each fraction on
Nataly_w [17]

Answer:

The Right Equivalent Fraction for the give Fractions are,

\dfrac{1}{2}   ------------------>  \dfrac{6}{12}    

\dfrac{6}{8}   ------------------>  \dfrac{3}{4}    

\dfrac{4}{5}   ------------------>  \dfrac{8}{10}    

\dfrac{2}{3}   ------------------>  \dfrac{8}{12}  

\dfrac{10}{12}   ------------------>  \dfrac{5}{6}      

Step-by-step explanation:

The Right Equivalent Fraction for the give Fractions are,

\dfrac{1}{2}   ------------->  \dfrac{6}{12}=\dfrac{6}{6\times 2}    

\dfrac{6}{8}=\dfrac{2\times 3}{2\times 4}  --------------->  \dfrac{3}{4}    

\dfrac{4}{5}   ------------------>  \dfrac{8}{10}=\dfrac{2\times 4}{2\times 5}    

\dfrac{2}{3}   ------------------>  \dfrac{8}{12}=\dfrac{4\times 2}{4\times 3}  

\dfrac{10}{12}=\dfrac{2\times 5}{2\times 6}   ------------------>  \dfrac{5}{6}      

The Right Equivalent Fraction for the give Fractions are,

\dfrac{1}{2}   ------------------>  \dfrac{6}{12}    

\dfrac{6}{8}   ------------------>  \dfrac{3}{4}    

\dfrac{4}{5}   ------------------>  \dfrac{8}{10}    

\dfrac{2}{3}   ------------------>  \dfrac{8}{12}  

\dfrac{10}{12}   ------------------>  \dfrac{5}{6}      

6 0
4 years ago
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