F(x) = x^5 - x^3 + x
f'(x) = 5x^4 - 3x^2 + 1
f(3) = (3)^5 - (3)^3 + 3 = 243 - 27 + 3 = 219
f'(3) = 5(3)^4 - 3(3)^2 + 1 = 5(81) - 3(9) + 1 = 405 - 27 + 1 = 379
Let the required equation of the tangent line be
y = mx + c; where y = 219, m = 379, x = 3
219 = 379(3) + c = 1,137
c = 219 - 1,137 = -918
Therefore, required equation is
y = 379x - 918
Its -1/2 because they are 9/4 then 7/4 then 5/4 then 3/4 and thats -2/4 which is equal to -1/2
Answer:
A, and D
Step-by-step explanation:
A works because when you multiply like bases, you add exponents, so we have...
5^7*5^-4 = 5^(7+(-4)) = 5^(7 -4) = 5^3
B doesn't work because when you divide like bases, you subtract the exponent of the denominator from the exponent of the denominator...
5^12/5^4 = 5^(12 - 4) = 5^8
C doesn't work because there is addition.
5 + 5² = 5 + 25 = 30, and 5³ = 125
D works because 5^0 = 1, so we have
5^0(5^3) = 1(5^3) = 5^3
E doesn't work because there is subtraction...
5^3 - 5^0 = 5^3 - 1 = 124
Answer:
Please see attached images for solution.
Step-by-step explanation:
Answer: P(sum is 5 or lower) = 10/36 (not simplified) = 5/18 (simplified)
Step-by-step explanation: The event is {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}
