Question

Please help what is the area

Answer 1

Given:

The figure of a trapezoid.

Length of mid-segment = 5.5

Height of the trapezoid = $6\sqrt{3}$

To find:

The area of the trapezoid.

Solution:

The area of a trapezoid is:

$A=M\times h$       ...(i)

$A=\dfrac{a+b}{2}\times h$

Where, a,b are bases and h is the vertical height.

We know that $M=\dfrac{a+b}{2}$ is the length of the mid-segment.

Putting M=5.5 and $h=6\sqrt{3}$ in (i), we get

$A=5.5\times 6\sqrt{3}$

$A=33\sqrt{3}$

Therefore, the area of the trapezoid is $33\sqrt{3}$ units squared.