Question

Solve for xxx. Write the smaller solution first, and the larger solution second. Round to two decimal places. (x + 3)^2 - 3 = 0

Answer 1

Answer:

x=-4.73 and -1.26

Step-by-step explanation:

We need to solve the given equation for x.

$(x + 3)^2 - 3 =0$

Solving the above equation using formula (a+b)² =a²+2ab+b²

$(x + 3)^2 - 3 =0\\\\x^2+9+6x-3=0\\\\x^2+6x+6=0$

It is a quadratic equation.

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

We have, a = 1, b = 6 and c = 6

$x=\dfrac{-6\pm \sqrt{(6)^2-4\times 1\times 6} }{2\times 1}\\\\x=\dfrac{-6+\sqrt{(6)^{2}-4\times1\times6}}{2\times1},\dfrac{-6-\sqrt{(6)^{2}-4\times1\times6}}{2\times1}\\\\x=-1.267, -4.73$

So, the values of x are -4.73 and -1.26