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3 years ago

Can someone please please help

Mathematics

1 answer:

bazaltina [42]3 years ago

3 0

Answer:No

Step-by-step explanation:The side lengths do not make a right triangle, so it can't be tangent.

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A 8.5 B 8.1 C 12.5 D 12.9

elena55 [62]

Cosine again. Yay.

Put 36 into a fancy calculator with one of those cos() things. You get about 0.81.

So that's the ratio between x and 10.

So basically x/10 = 0.81, or 0.81 * 10 = x.

8.1 = x

4 0

3 years ago

What is the value of the expression f(-3) + 2f(-1) - f (4) PLEASE HELP NO LINKS

Bas_tet [7]

Answer:

Step-by-step explanation:

Find f(-3) :

f(x) = x² + 2x for x ≤ -3

That means for those values of x, less than or equal to -3, this is the function.

So, f(-3) = (-3)² + 2(-3) = 9 - 6 = 3

Now, f(-1) :

From the given data, we see it is: f(x) = 2 $(\frac{1}{3} )^{2x}$

We take this because -1 lies between -3 and 4.

Now, f(-1) = 2 $(\frac{1}{3} )^{2(-1)}$

=> $f = (-1) = 2(3)^{2} = 2 (9) = 18$

For f(4) :

Clearly, the function is: $f (x) = \frac{2x - 5}{x-7}$

$f (4) = \frac{2(4)-5}{4-7} = \frac{3}{-3} = -1$

Therefore, f(-3) + f(-1) - f(4) = 3 + 18 - (-1) = 3 + 18 + 1 = 22.

5 0

3 years ago

10 donuts were eaten out of the 25 donuts paced.What % of donuts was eaten?

Anna11 [10]

Answer:

40%

Step-by-step explanation:

10/25= x/100

25x=1000

25 divided by 1000 =40%

4 0

3 years ago

a freight train must approach a road crossing at 16 km/h. After passing through the intersection, the train speeds up rto 65km/h

grin007 [14]

v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s

v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s

t = time to do so = 10 min = 10 x 60 sec = 600 sec

acceleration is given as

a = (v - v₀ )/t

a = (18.06 - 4.44)/(600)

a = 0.023 m/s²

a = 294

3 0

3 years ago

Plzzz helpppppp!!!!!!

Tema [17]

Answer:

Step-by-step explanation:

Given

The attached graph

Required

Find h(3)

The formula to use in solving this is:

$y = h(x)$

Substitute 3 for x

$y = h(3)$

From the attached graph, the value od x = 3 points to the value of y = 1.

So, we have:

$y = 1$

5 0

3 years ago