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MissTica
3 years ago
10

10) A new car is available in a sedan model and

Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:

Option (C) n = 256

Therefore, there are 256 ways to select a car with 2 car models, 8 different colors and any combinations of 4 optional features.

Step-by-step explanation:

A new car is available in a sedan model and a hatchback model.

So that means customers can select the model of the car in,

n₁ = 2 ways

It is available in eight  different colors.

After selecting the model, customers can select the color of the car in,

n₂ = 8 ways

Customers can choose to add any combination of four optional features.

After selecting the color, customers have the choice to add any combination of 4 optional features,

n₃ = 4² = 16 ways

Which means that there are 16 different ways to add 4 optional features e.g.

1. 0, 0, 0, 0

2. 0, 0, 0, 1

3. 0, 0, 1, 0

4. 0, 0, 1, 1

and the list goes on to 16 different ways.

Now the total ways to select a car is given by

n = n₁*n₂*n₃

n = 2*8*16

n = 256

Therefore, there are 256 ways to select a car with 2 car models, 8 different colors and any combinations of 4 optional features.

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Gennadij [26K]

Question

Which expression is equivalent to \frac{4mn}{m^{-2}n^6}. Assuming m \neq 0; n\neq 0

Answer:

\frac{4m^3}{n^5}

Step-by-step explanation:

Given

\frac{4mn}{m^{-2}n^6}

Required:

Simplify

To simplify this, we start by splitting each individual function

\frac{4mn}{m^{-2}n^6} = \frac{4m}{m^{-2}} * \frac{n}{n^6}

From laws of indices

\frac{a^x}{a^y} = a^{x-y}

SO, the above expression can also be expressed the same way

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1-(-2)} * n^{1-6}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1+2)} * n^{1-6}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * n^{-5}

From laws of indices,

a^{-x} = \frac{1}{a^x}

So,

\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * \frac{1}{n^5}

\frac{4m}{m^{-2}} * \frac{n}{n^6} = \frac{4m^3}{n^5}

Hence, \frac{4mn}{m^{-2}n^6} is equivalent to \frac{4m^3}{n^5}

5 0
3 years ago
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