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2 years ago

Which values of x are solutions to the equation below?

Mathematics

1 answer:

Anuta_ua [19.1K]2 years ago

3 0

Answer:

-5,5

Step-by-step explanation:

move the constant to the right to make it

3x^2=33+42

3x^2=75

divide both sides by 3

x^2=25

sq root of 25 is 5 and -5

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What is the parent function of g(x)=-3f(x+2). NEED HELP ASAP.

bezimeni [28]

Answer:

f ( x ) = x

Step-by-step explanation:

The parent function is the simplest form of the type of function given

8 0

3 years ago

If a piece of ribbon is 6 and 1 over 4. feet long, how long is it in inches?

timama [110]

The piece of ribbon would be 75 inches. The ribbon would be 75 inches because 1 foot would be 12 inches and you would multiply 12 by 6 to get 72. Then, 1/4 of a foot would be 3 inches because you could divide 12 and 4(the denominator you are dealing with) to get 3. Then, add 72 + 3 to get 75. Hope this helps!

5 0

3 years ago

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

all real numbers are solutions

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

no solution

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago

Consider the following problem: a box with an open top is to be constructed from a square piece of cardboard, 3 feet wide, by cu

Alecsey [184]

Answer:

) See annex

b) See annex

x = 0,5 ft

y = 2 ft and

V = 2 ft³

Step-by-step explanation: See annex

c) V = y*y*x

d-1) y = 3 - 2x

d-2) V = (3-2x)* ( 3-2x)* x ⇒ V = (3-2x)²*x

V(x) =( 9 + 4x² - 12x )*x ⇒ V(x) = 9x + 4x³ - 12x²

Taking derivatives

V¨(x) = 9 + 12x² - 24x

V¨(x) = 0 ⇒ 12x² -24x +9 = 0 ⇒ 4x² - 8x + 3 = 0

Solving for x (second degree equation)

x =[ -b ± √b²- 4ac ] / 2a

we get x₁ = 1,5 and x₂ = 0,5

We look at y = 3 - 2x and see that the value x₂ is the only valid root

then

x = 0,5 ft

y = 2 ft and

V = 0,5*2*2

V = 2 ft³

7 0

3 years ago

Just number 14 pls Zoom in if needed

o-na [289]

A, dilation because the shape got larger. The other three options just move it around

8 0

3 years ago