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lina2011 [118]
3 years ago
10

Does the point (2, 3) lie on the graph of y =3x-4? explain.

Mathematics
1 answer:
olasank [31]3 years ago
7 0
The y intercept is (0,-4) and we know the slope is 3. So yes (2,3) is a point on the line y=3x-4
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What are the truck ID’s of trucks that have carried small shipments. Small shipments are defined as those that weigh less than 8
Ivanshal [37]

Table for the question is attached in the picture below :

Answer:

SELECT distinct(TRUCK_ID), WEIGHT from SHIPMENT where WEIGHT < 800 ;

Step-by-step explanation:

The Structured query language (SQL) defined above, returns only the TRUCK_ID and Weight column from the shipment table as they are the only two columns listed after the select keyword. The condition is added using the WHERE keyword on the weight table, this filters the result returned to include only rows where the weight value is less than 800. The distinct keyword used alongside the TRUCK_ID column ensures that a certian TRUCK_ID value isn't returned more than once (Hence, it is used to avoid duplicates).

5 0
3 years ago
The vertices of quadrilateral PQRS are listed.
sladkih [1.3K]

Answer. : C. Quadrilateral PQRS is a rectangle.

Step-by-step explanation: Plato

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3 years ago
PORFAVOR NECESITO AYUDA CON LA PREGUNTAS ANTERIORES Q HICE PORFA AYUDENME!!!!
Black_prince [1.1K]

Answer:

Where are the questions?

Step-by-step explanation:

6 0
3 years ago
12.) A rectangular garden bas a perimeter of 50 feet. The width of the garden is 7 feet. What is the area of the garden? 50 feet
amid [387]
U need to find the length
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6 0
3 years ago
Read 2 more answers
Suppose that the population​ P(t) of a country satisfies the differential equation dP/dt = kP (600 - P) with k constant. Its pop
jeka94

Answer:

The country's population for the year 2030 is 368.8 million.

Step-by-step explanation:

The differential equation is:

\frac{dP}{dt}=kP(600 - P)\\\frac{dP}{P(600 - P)} =kdt

Integrate the differential equation to determine the equation of P in terms of <em>t</em> as follows:

\int\limits {\frac{1}{P(600-P)} } \, dP =k\int\limits {1} \, dt \\(\frac{1}{600} )[(\int\limits {\frac{1}{P} } \, dP) - (\int\limits {\frac{}{600-P} } \, dP)]=k\int\limits {1} \, dt\\\ln P-\ln (600-P)=600kt+C\\\ln (\frac{P}{600-P} )=600kt+C\\\frac{P}{600-P} = Ce^{600kt}

At <em>t</em> = 0 the value of <em>P</em> is 300 million.

Determine the value of constant C as follows:

\frac{P}{600-P} = Ce^{600kt}\\\frac{300}{600-300}=Ce^{600\times0\times k}\\\frac{1}{300} =C\times1\\C=\frac{1}{300}

It is provided that the population growth rate is 1 million per year.

Then for the year 1961, the population is: P (1) = 301

Then \frac{dP}{dt}=1.

Determine <em>k</em> as follows:

\frac{dP}{dt}=kP(600 - P)\\1=k\times300(600-300)\\k=\frac{1}{90000}

For the year 2030, P (2030) = P (70).

Determine the value of P (70) as follows:

\frac{P(70)}{600-P(70)} = \frac{1}{300} e^{\frac{600\times 70}{90000}}\\\frac{P(70)}{600-P(70)} =1.595\\P(70)=957-1.595P(70)\\2.595P(70)=957\\P(70)=368.786

Thus, the country's population for the year 2030 is 368.8 million.

3 0
4 years ago
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