Square Perimeter = 4(4x-1)
Rectangle Perimeter = 2(2x+1) + 2(x+2)
Square Perimeter = Rectangle Perimeter
4(4x-1) = 2(2x+1) + 2(x+2)
16x - 4 = 4x + 2 + 2x + 4
16x - 4 = 6x + 6
-6x +4 -6x +4
10x = 10
x = 1
Answer:
$289 I think
Step-by-step explanation:
$289 I think
sorry if I am wrong
A Beards, Beards where a fashion choice back then, just like how wemon had black teeth and white painted faces!
The inverse, converse and contrapositive of a statement are used to determine the true values of the statement
<h3>How to determine the inverse, converse and contrapositive</h3>
As a general rule, we have:
If a conditional statement is: If p , then q .
Then:
- Inverse -> If not p , then not q .
- Converse -> If q , then p .
- Contrapositive -> If not q , then not p .
Using the above rule, we have:
<u>Statement 1</u>
- Inverse: If a parallelogram does not have a right angle, then it is not a rectangle.
- Converse: If a parallelogram is a rectangle, then it has a right angle.
- Contrapositive: If a parallelogram is a not rectangle, then it does not have a right angle.
All three statements above are true
<u>Statement 2</u>
- Inverse: If two angles of one triangle are not congruent to two angles of another, then the third angles are not congruent.
- Converse: If the third angles of two triangle are congruent, then the two angles are congruent to two angles of another
- Contrapositive: If the third angles of two triangle are not congruent, then the two angles are not congruent to two angles of another
All three statements above are also true
Read more about conditional statements at:
brainly.com/question/11073037
Answer:
2 sqrt(5) OR 4.5
Step-by-step explanation:
You have to know Pythagorean theorem to solve this question.
a^2 + b^2 = c^2
To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:
b^2 + 8^2 = 10^2
But it would've come out the same. The unlabeled side is 6.
We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.
4^2 + x^2 = 6^2
16 + x^2 = 36 subtract 16 from both sides.
x^2 = 20
Take the square root of both sides.
sqrt (x^2) = sqrt 20
x = 2 sqrt(5) which is approximately 4.472.
2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.
